当我们通过devise_invitble(当发送初始邀请时)创建帐户时,我陷入困境并且不确定如何向用户添加“account_id”。
基本工作流程是所有者创建帐户,然后帐户所有者可以邀请某人使用应用程序设计可邀请。我需要跟踪用户与帐户的关联,因为帐户只有基于计划类型的“x”个用户。
class InvitationsController < Devise::InvitationsController
after_action :update_user_account, :only => [:create]
def update_user_account
@user = User.find_by_email(params[:user][:email])
@user.update_attributes(:account_id => current_account.id )
end
end
这就是我现在正在使用的,但是当我在rails控制台中将该用户拉出来并在服务器输出中查看它时,用户account_id仍为零。
这是帐户模型:
class Account < ApplicationRecord
include ImageUploader[:image]
# Constants
RESTRICTED_SUBDOMAINS = %w(www patrolvault admin test type taurenapplabs taurenmaterialservices)
# Before Actions
before_validation :downcase_subdomain
# Relationships
belongs_to :owner, class_name: 'User', optional: true
accepts_nested_attributes_for :owner
has_many :users
# Validations
validates :owner, presence: true
validates :subdomain, presence: true,
uniqueness: { case_sensitive: false },
format: { with: /\A[\w\-]+\Z/i, message: 'Contains invalid characters.' },
exclusion: { in: RESTRICTED_SUBDOMAINS, message: 'Restricted domain name'}
has_one :plan
accepts_nested_attributes_for :plan
private
def downcase_subdomain
self.subdomain = self.subdomain.downcase
end
end
这是用户模型:
class User < ApplicationRecord
# Constants & Enums
USER_LIMITS = ActiveSupport::HashWithIndifferentAccess.new(
#Plan Name #Auth Users
responder: 6,
first_responder: 12,
patrol_pro: 30,
guardian: 60
)
# Before Actions
# Devise Modules
devise :database_authenticatable, :registerable, :recoverable, :rememberable, :trackable, :validatable, :confirmable, :invitable, :lockable, :timeoutable
# Relationships
belongs_to :account, optional: true
# Validations
validates :f_name, presence: true
validates :l_name, presence: true
validates :date_of_birth, presence: true
#validate :must_be_below_user_limit
# Custom Methods
def full_name
l_name.upcase + ", " + f_name
end
end
拜托,非常感谢这里的任何帮助!这真的让我很伤心。
答案 0 :(得分:2)
@user.update_attributes(:account_id => current_account.id )
失败,因为User模型上的验证未通过。解决此问题的一种方法是使用update_all更新用户记录,这是一种仅绕过验证的SQL方法:
def update_user_account
User.where(email: params[:user][:email]).update_all(account_id: current_account.id)
end
答案 1 :(得分:1)
或更少的代码:
def create
super
User.where(email: params[:user][:email]).update_all(account_id: current_user.account.id)
end