Question

所以Heres我的代码

while True:
    username = raw_input("Username:")
    time.sleep(1)
    print username
    qwerty = raw_input("Is this right?")
    if qwerty == 'yes' or "Yes" or "Yeah" or "yeah" or "yup" or "Yup":
        print "OK."
        break
    elif qwerty == 'no' or 'No' or 'nope' or 'Nope' or 'nah' or 'Nah':
        print "Please type your Username again"
        continue
    else:
        print "Please Try a more common answer"
        continue`

我不知道什么是错的，因为我输入的内容只有第一个选项出来。有谁知道为什么？

Answer 1

您需要在document.addEventListener('DOMContentLoaded', function () { if (!Notification) { alert('Desktop notifications not available in your browser. Try Google Chrome.'); return; } if (Notification.permission !== "granted") Notification.requestPermission(); }); function timerFinishNotify() { if (Notification.permission !== "granted") Notification.requestPermission(); else { var notification = new Notification('Break Time!', { icon: '../img/icon.png', body: 'You worked hard, time for a break.', }); notification.onclick = function () { window.focus(), this.close(); }; } }; function breakFinishNotify() { var notification = new Notification('Work Time!', { icon: '../img/icon.png', body: 'Break time is over, time to be productive.', }); notification.onclick = function () { window.focus(), this.close(); }; };中将条件更新为：

if

解释：

Python中的

if qwerty in ['yes', "Yes", "Yeah", "yeah", "yup", "Yup"]执行逻辑or操作。如果值为OR，则满足条件，否则它将转到True中的下一个条件。为了让您更清晰。例如：

or

另请注意，python将非零和非空字符串值视为>>> 'Hello' or 'Man' 'Hello' >>> '' or 'Man' 'Man'。

您的案例示例：

True

我的If语句只选择第一个选项

1 个答案: