我有一个类似的字符串:
String msg=
<?xml version="1.0" encoding="UTF-8" standalone="no">
<validateEmail>
<emailid>abc@gmail.com</emailid>
<instanceid>instance1</instanceid>
<msgname>validatemsg</msgname>
<taskid>task1</taskid>
</validateEmail>
我如何将此字符串转换为xml文件并附加新节点。
谢谢
答案 0 :(得分:3)
此代码将您的String转换为XML文档,添加一个新节点,然后将其打印为String,以便检查它是否正确。
public void xml() throws ParserConfigurationException, SAXException, IOException {
String msg = "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\"?>";
msg += "<validateEmail><emailid>abc@gmail.com</emailid><instanceid>instance1</instanceid>";
msg += "<msgname>validatemsg</msgname><taskid>task1</taskid></validateEmail>";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(new ByteArrayInputStream(msg.getBytes()));
Node newNode = doc.createElement("newnode");
newNode.setTextContent("value");
Node root = doc.getFirstChild();
root.appendChild(newNode);
try {
DOMSource domSource = new DOMSource(doc);
StringWriter writer = new StringWriter();
StreamResult result = new StreamResult(writer);
TransformerFactory tf = TransformerFactory.newInstance();
Transformer transformer = tf.newTransformer();
transformer.transform(domSource, result);
System.out.println(writer.toString());
} catch (TransformerException ex) {
ex.printStackTrace();
}
}
答案 1 :(得分:1)
首先创建一个表示XML的DOM(文档对象模型)对象。
byte[] xmlBytes = msg.getBytes("UTF-8");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new ByteArrayInputStream(xmlBytes));
然后您需要将新节点添加到其中:
Element newNode = doc.createElement("myNode");
newNode.setTextContent("contents of node");
Element root = doc.getDocumentElement(); // the <validateEmail>
root.appendChild(newNode);
如果我正确理解了这个问题,那么你想将它写入文件系统。
File outputFile = ...;
Source source = new DOMSource(doc);
Result result = new StreamResult(outputFile);
Transformer xformer = TransformerFactory.newInstance().newTransformer();
xformer.transform(source, result);