对象空数组上的Javascript推送列表

Question

我正在尝试从对象中获取标签列表

以下是完整的代码和数据：

$(document).ready(function() {

obj = 

{
    "category":[
    {

    "id":"8098",
        "tags":{
            "411":"something",
            "414":"something else"
        }
    }

]

};


var tagList = [];

for (var index in obj) {

  for (var indexSub in obj[index].tags) {

       blah = (obj[index].tags[indexSub]);
       tagList.push(blah);
   }
}

console.log(tagList);



});

这是指向jsFiddle

的链接

问题是taglist返回一个空数组。

我该如何解决这个问题？

Answer 1

此致

    for (var index in obj) {

        for (var indexSub in obj[index].tags) {

            blah = (obj[index].tags[indexSub]);
            tagList.push(blah);
        }
    }

获取tags

中category的新内容

for (var index in obj) {
  for (var indexSub in obj[index]) {
     blah = (obj[index][indexSub].tags);
     tagList.push(blah);
  }
} 

查看访问属性

的方式的差异

 
        obj =
            {
                "category": [
                    {
                        "id": "8098",
                        "tags": {
                            "411": "something",
                            "414": "something else"
                        }
                    }

                ]

            };


        var tagList = [];

        for (var index in obj) {

            for (var indexSub in obj[index]) {
                tagList = (obj[index][indexSub].tags);
               // tagList.push(blah);
            }
        }

        console.log(tagList);

Answer 2

你需要迭代这个类别，然后获取标签的键和值，像这样的东西。

var obj = 
{
    "category":[
    {

    "id":"8098",
        "tags":{
            "411":"something",
            "414":"something else"
        }
    }

]};

var tagList = [];

obj.category.forEach( o =>{
  for (property in o.tags){
   tagList.push(property + ':'+ o.tags[property]);  
  };
});

console.log(tagList);

Answer 3

这是您的jsfiddle

obj = 
{
   "category":[
          {
             "id":"8098",
             "tags":{
                 "411":"something",
                 "414":"something else"
             }
          }

   ]
};
var tagList = [];
for (key in obj) {
    for(subKey in obj[key]){
            var myTags=obj[key][subKey].tags;
            for(tag in myTags){
                 tagList.push(tag);
            }
    }

}
console.log(tagList);

Answer 4

您可以使用Array#reduce和Object.keys与Array#map进行迭代并获取所有代码。

var obj = { "category": [{ "id": "8098", "tags": { "411": "something", "414": "something else" } }] },
    tagList = obj.category.reduce(function (r, a) {
        return r.concat(Object.keys(a.tags).map(function (t) { return a.tags[t]; }));
    }, []);

console.log(tagList);