Question

我的路径是\\server\folderName1\another name\something\another folder\

如果我不知道路径中有多少文件夹而且我不知道文件夹名称，如何将每个文件夹名称提取为字符串？

非常感谢

Answer 1

string mypath = @"..\folder1\folder2\folder2";
string[] directories = mypath.Split(Path.DirectorySeparatorChar);

编辑：这将返回目录数组中的每个单独的文件夹。您可以获得这样返回的文件夹数：

int folderCount = directories.Length;

Answer 2

这在一般情况下是好的：

yourPath.Split(@"\/", StringSplitOptions.RemoveEmptyEntries)

如果路径本身以（后退）斜杠结尾（例如“\ foo \ bar \”），则返回的数组中没有空元素。但是，您必须确保yourPath实际上是一个目录而不是文件。你可以找出它是什么，并补偿它是否是这样的文件：

if(Directory.Exists(yourPath)) {
  var entries = yourPath.Split(@"\/", StringSplitOptions.RemoveEmptyEntries);
}
else if(File.Exists(yourPath)) {
  var entries = Path.GetDirectoryName(yourPath).Split(
                    @"\/", StringSplitOptions.RemoveEmptyEntries);
}
else {
  // error handling
}

我相信这涵盖了所有基础，而不是太迂腐。它将返回string[]，您可以使用foreach进行迭代，以便依次获取每个目录。

如果要使用常量而不是@"\/"魔术字符串，则需要使用

var separators = new char[] {
  Path.DirectorySeparatorChar,  
  Path.AltDirectorySeparatorChar  
};

然后在上面的代码中使用separators代替@"\/"。就个人而言，我觉得这个问题太冗长了，很可能不会这样做。

Answer 3

我看到你的method Wolf5370并举起你。

internal static List<DirectoryInfo> Split(this DirectoryInfo path)
{
    if(path == null) throw new ArgumentNullException("path");
    var ret = new List<DirectoryInfo>();
    if (path.Parent != null) ret.AddRange(Split(path.Parent));
    ret.Add(path);
    return ret;
}

在路径c:\folder1\folder2\folder3上返回

c:\

c:\folder1

c:\folder1\folder2

c:\folder1\folder2\folder3

按顺序

OR

internal static List<string> Split(this DirectoryInfo path)
{
    if(path == null) throw new ArgumentNullException("path");
    var ret = new List<string>();
    if (path.Parent != null) ret.AddRange(Split(path.Parent));
    ret.Add(path.Name);
    return ret;
}

将返回

c:\

folder1

folder2

folder3

Answer 4

意识到这是一篇很老的帖子，但我看到了它 - 最后我决定使用下面的功能，因为它对当时我正在做的事情进行了比上述任何一项更好的选择：

private static List<DirectoryInfo> SplitDirectory(DirectoryInfo parent)
{
    if (parent == null) return null;
    var rtn = new List<DirectoryInfo>();
    var di = parent;

    while (di.Name != di.Root.Name)
    {
    rtn.Add(new DirectoryInfo(di));
    di = di.Parent;
    }
    rtn.Add(new DirectoryInfo(di.Root));

    rtn.Reverse();
    return rtn;
}

Answer 5

public static IEnumerable<string> Split(this DirectoryInfo path)
{
    if (path == null) 
        throw new ArgumentNullException("path");
    if (path.Parent != null)
        foreach(var d in Split(path.Parent))
            yield return d;
    yield return path.Name;
}

Answer 6

    // - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
    /// <summary>
    /// Use to emulate the C lib function _splitpath()
    /// </summary>
    /// <param name="path">The path to split</param>
    /// <param name="rootpath">optional root if a relative path</param>
    /// <returns>the folders in the path. 
    ///     Item 0 is drive letter with ':' 
    ///     If path is UNC path then item 0 is "\\"
    /// </returns>
    /// <example>
    /// string p1 = @"c:\p1\p2\p3\p4";
    /// string[] ap1 = p1.SplitPath();
    /// // ap1 = {"c:", "p1", "p2", "p3", "p4"}
    /// string p2 = @"\\server\p2\p3\p4";
    /// string[] ap2 = p2.SplitPath();
    /// // ap2 = {@"\\", "server", "p2", "p3", "p4"}
    /// string p3 = @"..\p3\p4";
    /// string root3 = @"c:\p1\p2\";
    /// string[] ap3 = p1.SplitPath(root3);
    /// // ap3 = {"c:", "p1", "p3", "p4"}
    /// </example>
    public static string[] SplitPath(this string path, string rootpath = "")
    {
        string drive;
        string[] astr;
        path = Path.GetFullPath(Path.Combine(rootpath, path));
        if (path[1] == ':')
        {
            drive = path.Substring(0, 2);
            string newpath = path.Substring(2);
            astr = newpath.Split(new[] { Path.DirectorySeparatorChar }
                , StringSplitOptions.RemoveEmptyEntries);
        }
        else
        {
            drive = @"\\";
            astr = path.Split(new[] { Path.DirectorySeparatorChar }
                , StringSplitOptions.RemoveEmptyEntries);
        }
        string[] splitPath = new string[astr.Length + 1];
        splitPath[0] = drive;
        astr.CopyTo(splitPath, 1);
        return splitPath;
    }

Answer 7

快速回答是使用.Split（'\\'）方法。

Answer 8

也许在循环中调用Directory.GetParent？如果你想要每个目录的完整路径而不仅仅是目录名。

Answer 9

受到早期答案的启发，但更简单，而且没有递归。另外，它也不在乎分隔符号是什么，因为Dir.Parent涵盖了这一点：

    /// <summary>
    /// Split a directory in its components.
    /// Input e.g: a/b/c/d.
    /// Output: d, c, b, a.
    /// </summary>
    /// <param name="Dir"></param>
    /// <returns></returns>
    public static IEnumerable<string> DirectorySplit(this DirectoryInfo Dir)
    {
        while (Dir != null)
        {
            yield return Dir.Name;
            Dir = Dir.Parent;
        }
    }

要么将其放在static类中以创建一个不错的扩展方法，要么就不添加this（和static）。

使用示例（作为扩展方法）按数字访问路径部分：

    /// <summary>
    /// Return one part of the directory path.
    /// Path e.g.: a/b/c/d. PartNr=0 is a, Nr 2 = c.
    /// </summary>
    /// <param name="Dir"></param>
    /// <param name="PartNr"></param>
    /// <returns></returns>
    public static string DirectoryPart(this DirectoryInfo Dir, int PartNr)
    {
        string[] Parts = Dir.DirectorySplit().ToArray();
        int L = Parts.Length;
        return PartNr >= 0 && PartNr < L ? Parts[L - 1 - PartNr] : "";
    }

以上两种方法现在都在我的个人库中，因此是xml注释。用法示例：

    DirectoryInfo DI_Data = new DirectoryInfo(@"D:\Hunter\Data\2019\w38\abc\000.d");
    label_Year.Text = DI_Data.DirectoryPart(3); // --> 2019
    label_Entry.Text = DI_Data.DirectoryPart(6);// --> 000.d

Answer 10

我用它来循环文件夹 ftp 服务器

public List<string> CreateMultiDirectory(string remoteFile)
      
var separators = new char[] { Path.DirectorySeparatorChar, Path.AltDirectorySeparatorChar };
string[] directory = Path.GetDirectoryName(remoteFile).Split(separators);

var path = new List<string>();
var folder = string.Empty;
foreach (var item in directory)
{
     folder += $@"{item}\";
     path.Add(folder);
}

return path;

Answer 11

有几种方法可以表示文件路径。您应该使用System.IO.Path类来获取操作系统的分隔符，因为它可能因UNIX和Windows而异。此外，大多数（或所有，如果我没有记错）.NET库接受'\'或'/'作为路径分隔符，无论操作系统如何。出于这个原因，我将使用Path类来拆分路径。尝试以下内容：

string originalPath = "\\server\\folderName1\\another\ name\\something\\another folder\\";
string[] filesArray = originalPath.Split(Path.AltDirectorySeparatorChar,
                              Path.DirectorySeparatorChar);

无论文件夹数量或名称如何，这都应该有效。

Answer 12

我正在补充Matt Brunell的答案。

            string[] directories = myStringWithLotsOfFolders.Split(Path.DirectorySeparatorChar);

            string previousEntry = string.Empty;
            if (null != directories)
            {
                foreach (string direc in directories)
                {
                    string newEntry = previousEntry + Path.DirectorySeparatorChar + direc;
                    if (!string.IsNullOrEmpty(newEntry))
                    {
                        if (!newEntry.Equals(Convert.ToString(Path.DirectorySeparatorChar), StringComparison.OrdinalIgnoreCase))
                        {
                            Console.WriteLine(newEntry);
                            previousEntry = newEntry;
                        }
                    }
                }
            }

这应该给你：

“\服务器”

“\服务器\ folderName1”

“\ server \ folderName1 \ another name”

“\ server \ folderName1 \ another name \ something”

“\ server \ folderName1 \ another name \ something \ another folder \”

（或按照每个值的string.Length对结果集合进行排序。

Answer 13

DirectoryInfo objDir = new DirectoryInfo(direcotryPath);
DirectoryInfo [] directoryNames =  objDir.GetDirectories("*.*", SearchOption.AllDirectories);

Answer 14

我写了以下方法，对我有用。

protected bool isDirectoryFound(string path, string pattern)
    {
        bool success = false;

        DirectoryInfo directories = new DirectoryInfo(@path);
        DirectoryInfo[] folderList = directories.GetDirectories();

        Regex rx = new Regex(pattern);

        foreach (DirectoryInfo di in folderList)
        {
            if (rx.IsMatch(di.Name))
            {
                success = true;
                break;
            }
        }

        return success;
    }

与您的问题最相关的行是：

DirectoryInfo目录=新的DirectoryInfo（@path）; DirectoryInfo [] folderList = directories.GetDirectories（）;

Answer 15

这里修改了沃尔夫的答案，遗漏了根并解决了几个错误。我用它来生成面包屑，我不想要显示根。

这是DirectoryInfo类型的扩展名。

public static List<DirectoryInfo> PathParts(this DirectoryInfo source, string rootPath)
{
  if (source == null) return null;
  DirectoryInfo root = new DirectoryInfo(rootPath);
  var pathParts = new List<DirectoryInfo>();
  var di = source;

  while (di != null && di.FullName != root.FullName)
  {
    pathParts.Add(di);
    di = di.Parent;
  }

  pathParts.Reverse();
  return pathParts;
}

Answer 16

我刚刚编写了此代码，因为我发现C＃中尚未内置任何代码。

/// <summary>
/// get the directory path segments.
/// </summary>
/// <param name="directoryPath">the directory path.</param>
/// <returns>a IEnumerable<string> containing the get directory path segments.</returns>
public IEnumerable<string> GetDirectoryPathSegments(string directoryPath)
{
    if (string.IsNullOrEmpty(directoryPath))
    { throw new Exception($"Invalid Directory: {directoryPath ?? "null"}"); }

    var currentNode = new System.IO.DirectoryInfo(directoryPath);

    var targetRootNode = currentNode.Root;
    if (targetRootNode == null) return new string[] { currentNode.Name };
    var directorySegments = new List<string>();
    while (string.Compare(targetRootNode.FullName, currentNode.FullName, StringComparison.InvariantCultureIgnoreCase) != 0)
    {
        directorySegments.Insert(0, currentNode.Name);
        currentNode = currentNode.Parent;
    }
    directorySegments.Insert(0, currentNode.Name);
    return directorySegments;
}

Answer 17

或者，如果您需要对每个文件夹执行某些操作，请查看System.IO.DirectoryInfo类。它还有一个Parent属性，允许您导航到父目录。

如何从路径中提取每个文件夹名称？

17 个答案:

OR