Question

表#Temp：

ID    Name        Hobbies
1     xxx          Reading
1     xxx          Sports
1     xxx          Dance
2     xyz          Dance
3     yyy          Swimming
3     yyy          Reading

现在，我希望结果集为：

ID   Name    Reading  Sports  Dance  Swimming  
1    xxx      T        T      T        F
2    xyz      F        F      T        F
3    yyy      T        F      F        T

我写了以下查询：

SELECT * FROM
(
    SELECT * FROM #Temp
)SRC
PIVOT
(
    COUNT([ID]) 
    FOR [Hobbies] in ([Reading],[Sports],[Dance],[Swimming])
) piv;

我得到了以下结果：

ID   Name    Reading  Sports  Dance  Swimming  
1    xxx      1        1      1        0
2    xyz      0        0      1        0
3    yyy      1        0      0        1

所以，我想在聚合中使用条件，例如if（count（id）= 1然后＆＃39; T＆＃39; else＆＃39; F＆＃39;）。是否有可能在Pivots中如何实现它？

Answer 1

试试这个

SELECT ID,NAME,
       CASE WHEN Reading=1 THEN 'T' ELSE 'F' END AS Reading,
       CASE WHEN Sports=1 THEN 'T' ELSE 'F' END AS Sports,
       CASE WHEN Dance=1 THEN 'T' ELSE 'F' END AS Dance,
       CASE WHEN Swimming =1 THEN 'T' ELSE 'F' END AS Swimming ,
FROM(
        --your query here
)t

Answer 2

SELECT 
    Name,
    CASE Reading WHEN 1 THEN 'T' ELSE 'F' END AS Reading,
    CASE Sports WHEN 1 THEN 'T' ELSE 'F' END AS Sports,
    CASE Dance WHEN 1 THEN 'T' ELSE 'F' END AS Dance,
    CASE Swimming WHEN 1 THEN 'T' ELSE 'F' END AS Swimming
FROM
(
    SELECT * FROM @tblTest
)SRC
PIVOT
(
    COUNT([ID]) 
    FOR [Hobbies] in ([Reading],[Sports],[Dance],[Swimming])
) piv;

Answer 3

SELECT case when Reading >0 then 'T' else 'F' end Reading ,
       case when Sports >0 then 'T' else 'F' end Sports ,
       case when Dance >0 then 'T' else 'F' end Dance 

FROM
(
    SELECT * FROM #Temp
)SRC
PIVOT
(
    COUNT([ID]) 
    FOR [Hobbies] in ([Reading],[Sports],[Dance],[Swimming])
) piv;

数据透视中聚合的条件

3 个答案: