interface IService<T> {}
class ConcreteServiceA<T> : IService<T> {}
我需要:
IService<string> stringServices = kernel.Get<IService<string>>();
ConcreteServiceA<string> concreteStringServiceA = kernel.Get<ConcreteServiceA<string>>();
Assert.IsSameReference(stringService, concreteStringServiceA);
到目前为止,我已尝试创建绑定:
this.Bind(typeof(IService<>))
.To(typeof(ConcreteServiceA<>))
.InSingletonScope();
this.Bind(typeof(ConcreteServiceA<>)).ToSelf().InSingletonScope();
尽管如此,使用此绑定我在请求IService<string>
和ConcreteServiceA<string>
时获得了两个不同的实例:
kernel.Get<IService<string>>() instance is different of kernel.Get<ConcreteService<string>>()
有什么想法吗?
答案 0 :(得分:2)
您可以指定多个要同时绑定的类型,例如:
kernel.Bind(typeof(IList<>)).To(typeof(List<>)).InSingletonScope();
kernel.Bind(typeof(List<>)).ToSelf().InSingletonScope();
var list1 = kernel.Get<IList<string>>();
var list2 = kernel.Get<List<string>>();
Assert.IsTrue(list1.Equals(list2)); // fails as per your question
kernel.Bind(typeof(IList<>), typeof(List<>)).To(typeof(List<>)).InSingletonScope();
var list1 = kernel.Get<IList<string>>();
var list2 = kernel.Get<List<string>>();
Assert.IsTrue(list1.Equals(list2)); // passes
我做了一些测试来证实这一点:
#!/usr/bin/env nodejs