所以我有3个数组。一个包含用户的名字,第二个包含用户的姓氏,第三个包含他们的姓氏。
数组有一个共同点,即键....所以user_first [0]属于user_last [0],它也与email [0]匹配,依此类推。
所以我想要一个新的数组:
Array
(
[0] => Array
(
[first_name] => John
[last_name] => Doe
[email] => john.doe@domain.com
)
[1] => Array
(
[first_name] => Jane
[last_name] => Doe
[email] => jane.doe@domain.com
)
)
而不是原始的,这将是:
Array
(
[0] => John
[1] => Jane
)
Array
(
[0] => Doe
[1] => Doe
)
Array
(
[0] => john.doe@domain.com
[1] => jane.doe@domain.com
)
答案 0 :(得分:0)
$combinedArray = array();
foreach($first_names as $key => $first_name)
{
$combinedArray[$key] = array(
"first_name" = $first_name,
"last_name" = $last_names[$key],
"email" = $emails[$key]
);
}
答案 1 :(得分:0)
只需在数组中使用数组,如
$a = array();
$a[] = array("first_name"=>"John","last_name" => "Doe", "email" => "john.doe@domain.com");
$a[] = array("first_name"=>"Jane","last_name" => "Doe", "email" => "jane.doe@domain.com");
这正是你想要的,即
array(2) {
[0]=>
array(3) {
["first_name"]=>
string(4) "John"
["last_name"]=>
string(3) "Doe"
["email"]=>
string(19) "john.doe@domain.com"
}
[1]=>
array(3) {
["first_name"]=>
string(4) "Jane"
["last_name"]=>
string(3) "Doe"
["email"]=>
string(19) "jane.doe@domain.com"
}
}
答案 2 :(得分:0)
尝试使用以下代码
<?php
$arr1 = array(
0 => "John",
1 => "Jane");
$arr2 = array
(
0 => "Doe",
1 => "Doe"
);
$arr3 =array
(
0 => "john.doe@domain.com",
1 => "jane.doe@domain.com"
);
$new_arr=[];
foreach ($arr1 as $key => $value) {
# code...
//echo $arr2[$key]."<br>";
$new_arr[$key]["first_name"]= $value;
$new_arr[$key]["last_name"]= $arr2[$key];
$new_arr[$key]["email"]= $arr3[$key];
}
echo "<pre>";
print_r($new_arr);
在此处查看演示:demo