Question

在脚本中运行此代码（从表单中获取详细信息）以获取用户组列表并从除“Group1”和“Group2”组之外的所有组中删除：

#remove any group memberships except Group1 and Group2
$groups = Get-ADPrincipalGroupMembership $Inputsamaccountname.Text | Where-Object -filter {$_.name -ne 'Group1' -And $_.name -ne 'Group2'} 
foreach ($group in $groups) {
    $group = $groups.Name 
    $RemovegroupMsg = "Removing " + $inputSamAccountName.Text + " from " + $group
    logentryDateTime $removeGroupMsg
    Remove-ADPrincipalGroupMembership -Identity $inputSamAccountName.Text -MemberOf $group -Confirm:$false
    if ($Error) {
        $errorMessage = "Error removing " + $inputSamAccountName.Text + " from " + $group + " " + ($Error[0].ToString()) + " continuing."
        logentryDateTime $errorMessage
        $Error.Clear()
        continue
    } elseif (!$Error) {
        Write-Output "" >> $outlogfile 
        logentryDateTime "Successfully removed " + $inputSamAccountName.Text + " from " + $group
    }
}

该脚本有效，您可以看到这些组已被删除，但是日志显示“无法将参数绑定到参数'Name'，因为它为null。”符合该条件的每个组的错误“：

[2016-10-19 113117-820] : Removing user.test1 from Other-group
[2016-10-19 113117-820] : Error removing user.test1 from Other-group Cannot bind argument to parameter 'Name' because it is null. continuing.

我知道在我错过的foreach循环的逻辑中，这可能是非常简单的。

Answer 1

这一行看起来像你的问题所在：$group = $groups.name看到你在foreach循环中访问数组（$groups）并迭代这些元素，这是令人惊讶的。您的意思是$group = $group.name吗？

foreach循环运行两次？

1 个答案: