如果否则不在C ++语句中工作

Question

如果他们不从其中一个选项中选择，我怎么会得到一个说错误颜色的else语句？我尝试过if else和else，但即使颜色有正确的选项，它也会显示在我的代码末尾。

我是新手......感谢您的帮助。

enter code here

#include <iostream>
#include <iomanip>
#include <string>
using namespace std;

int main()
{
    string color1, color2;
    string Red, Blue, Yellow;

    cout << "When you enter two primary colors, I will tell you\n";
    cout << "what color they make when they are mixed together.\n\n";
    cout << "Enter red, blue, or yellow: \n" << endl;
    getline(cin, color1);

    if (color1 == "red" || color1 == "Red")
    {
        cout << "Please choose from blue or yellow:\n";
        getline(cin, color2);

        if (color2 == "yellow" ||color2 == "Yellow")
        {
            cout << "\nGreat you make Orange.\n";
        }
        if (color2 == "Blue" || color2 == "blue")
        {
            cout << "\nGreat you make purple.\n";
        }
    }


    if (color1 == "yellow" || color1 == "Yellow")
    {
        cout << "Please choose from blue or red:\n";
        getline(cin, color2);

        if (color2 == "red" || color2 == "Red")
        {
            cout << "\nGreat you make Orange.\n";
        }
        if (color2 == "Blue" || color2 == "blue")
        {
            cout << "\nGreat you make Green.\n";
        }
    }

    if (color1 == "Blue" || color1 == "blue")
    {
        cout << "Please choose from yellow or red:\n";
        getline(cin, color2);

        if (color2 == "red" || color2 == "Red")
        {
            cout << "\nGreat you make Purple.\n";
        }
        if (color2 == "yellow" || color2 == "Yellow")
        {
            cout << "\nGreat you make Green.\n";
        }
    }
    return 0;
}

    enter code here