Question

这是我的代码：

print("Hello, what's your name?")
myName = sys.stdin.readline()
Join = input("Would you like to play a game, yes or no?").lower()
if Join.startswith('y'):
    print("Fine, you can play.")
else:
    print("Ok, goodbye.")
    sys.exit()
Color = input("So, first question. What's your favorite colour,
or do you have none?").lower()
if Color.startswith("n"):
    Thanks = input("Didn't expect much from you, good job", myName, 
" Say thanks, I complimented you!").lower()
else:
    print("Having a favorite colour is the wrong answer, try again.")
    sys.exit()
if Thanks.lower() == 'thanks':
    print("NEVER SAY THANKS!")
    sys.exit()
else:
    Continue = input("Well done, you didn't say THANKS. 
    Do you wish to  continue, yes or no?").lower()
if Continue.startswith('y'):
    print("Sure let's continue then.")
else:
    print("Too bad, you HAVE to continue!")
    sys.exit()

我是编程新手，而我只是制作了一个笑话＆＃34;代码练习。但是我一直在这条线上出错：

Thanks = input("Didn't expect much from you, good job", myName, " Say thanks, I complimented you!").lower()

错误是：

TypeError：输入最多需要1个参数，得到3

Answer 1

输入只有一个参数，你提供3。

要连接字符串，您可以使用+而不是,

Thanks = input("Didn't expect much from you, good job "+ myName + +" Say thanks, I complimented you!").lower()

Answer 2

请改为：

SELECT CONVERT('Ä Ê Í Õ Ø A B C D E ', 'UTF8', 'US7ASCII')

由于“，”，它将其作为参数获取并且不会连接字符串

Python：TypeError：输入最多需要1个参数，得到3

2 个答案: