Question

我的数据框类似于

from pyspark.sql.functions import avg, first

rdd = sc.parallelize(
[
(0, "A", 223,"201603", "PORT"), 
(0, "A", 22,"201602", "PORT"), 
(0, "A", 22,"201603", "PORT"), 
(0, "C", 22,"201605", "PORT"), 
(0, "D", 422,"201601", "DOCK"), 
(0, "D", 422,"201602", "DOCK"), 
(0, "C", 422,"201602", "DOCK"), 
(1,"B", 3213,"201602", "DOCK"), 
(1,"A", 3213,"201602", "DOCK"), 
(1,"C", 3213,"201602", "PORT"), 
(1,"B", 3213,"201601", "PORT"), 
(1,"B", 3213,"201611", "PORT"), 
(1,"B", 3213,"201604", "PORT"), 
(3,"D", 3999,"201601", "PORT"), 
(3,"C", 323,"201602", "PORT"), 
(3,"C", 323,"201602", "PORT"), 
(3,"C", 323,"201605", "DOCK"), 
(3,"A", 323,"201602", "DOCK"), 
(2,"C", 2321,"201601", "DOCK"),
(2,"A", 2321,"201602", "PORT")
]
)
df_data = sqlContext.createDataFrame(rdd, ["id","type", "cost", "date", "ship"])

我需要按id和type进行汇总，每组的ship出现次数最多。例如，

grouped = df_data.groupby('id','type', 'ship').count()

有一列，其中包含每组的次数：

+---+----+----+-----+
| id|type|ship|count|
+---+----+----+-----+
|  3|   A|DOCK|    1|
|  0|   D|DOCK|    2|
|  3|   C|PORT|    2|
|  0|   A|PORT|    3|
|  1|   A|DOCK|    1|
|  1|   B|PORT|    3|
|  3|   C|DOCK|    1|
|  3|   D|PORT|    1|
|  1|   B|DOCK|    1|
|  1|   C|PORT|    1|
|  2|   C|DOCK|    1|
|  0|   C|PORT|    1|
|  0|   C|DOCK|    1|
|  2|   A|PORT|    1|
+---+----+----+-----+

我需要

+---+----+----+-----+
| id|type|ship|count|
+---+----+----+-----+
|  0|   D|DOCK|    2|
|  0|   A|PORT|    3|
|  1|   A|DOCK|    1|
|  1|   B|PORT|    3|
|  2|   C|DOCK|    1|
|  2|   A|PORT|    1|
|  3|   C|PORT|    2|
|  3|   A|DOCK|    1|
+---+----+----+-----+

我尝试使用

的组合

grouped.groupby('id', 'type', 'ship')\
.agg({'count':'max'}).orderBy('max(count)', ascending=False).\
groupby('id', 'type', 'ship').agg({'ship':'first'})

但它失败了。有没有办法从一个组的计数中获取最大行？

在熊猫上，这个oneliner完成了这项任务：

df_pd = df_data.toPandas()
df_pd_t = df_pd[df_pd['count'] == df_pd.groupby(['id','type', ])['count'].transform(max)]

Answer 1

根据您的预期输出，您似乎只按id和ship进行分组 - 因为您已在grouped中拥有不同的值 - 因此会根据列删除重复的元素id，ship和count，按type排序。

为实现这一目标，我们可以使用Window函数：

from pyspark.sql.window import Window
from pyspark.sql.functions import rank, col

window = (Window
          .partitionBy(grouped['id'],
                       grouped['ship'])
          .orderBy(grouped['count'].desc(), grouped['type']))


(grouped
 .select('*', rank()
         .over(window)
         .alias('rank')) 
  .filter(col('rank') == 1)
  .orderBy(col('id'))
  .dropDuplicates(['id', 'ship', 'count'])
  .drop('rank')
  .show())
+---+----+----+-----+
| id|type|ship|count|
+---+----+----+-----+
|  0|   D|DOCK|    2|
|  0|   A|PORT|    3|
|  1|   A|DOCK|    1|
|  1|   B|PORT|    3|
|  2|   C|DOCK|    1|
|  2|   A|PORT|    1|
|  3|   A|DOCK|    1|
|  3|   C|PORT|    2|
+---+----+----+-----+

使用PySpark中的多个列从groupby获取具有最大值的行

1 个答案: