Question

SELECT  A.SPLIT, 

     SUM(CASE WHEN answer_time IS NOT NULL AND A.ent_split IS NOT NULL AND call_type NOT LIKE 'PBX%' THEN 1 ELSE 0 END) AS CH,
     SUM(CASE WHEN answer_time IS NOT NULL AND A.ent_split IS NOT NULL AND call_type NOT LIKE 'PBX%' THEN 1 ELSE 0 END) + SUM(CASE WHEN abandon_time IS NOT NULL  AND answer_time IS NULL THEN 1 ELSE 0 END) AS CO,
SUM(CASE WHEN answer_time IS NOT NULL AND A.ent_split IS NOT NULL AND call_type NOT LIKE 'PBX%' THEN 1 ELSE 1 END) AS AHT 
FROM    reporting_call_matrix AS A WITH (NOLOCK) 
WHERE  A.CALENDAR_DATE >= '10/01/2015' AND A.CALENDAR_DATE <= '9/30/2016' AND A.SPLIT IN (9,26,23,43,48,33,56,70,71,72,74,50) AND ( A.ent_split IS NOT NULL)
Group BY A.SPLIT

Heres是我的代码提出的一些数据。

              Split     CH      CO      AHT
                9     957157 1156319  1156461

Answer 1

你是说这个？

SELECT  A.SPLIT, A.CALENDAR_DATE,
     SUM(CASE WHEN answer_time IS NOT NULL AND A.ent_split IS NOT NULL AND call_type NOT LIKE 'PBX%' THEN 1 ELSE 0 END) AS CH,
     SUM(CASE WHEN answer_time IS NOT NULL AND A.ent_split IS NOT NULL AND call_type NOT LIKE 'PBX%' THEN 1 ELSE 0 END) + SUM(CASE WHEN abandon_time IS NOT NULL  AND answer_time IS NULL THEN 1 ELSE 0 END) AS CO,
SUM(CASE WHEN answer_time IS NOT NULL AND A.ent_split IS NOT NULL AND call_type NOT LIKE 'PBX%' THEN 1 ELSE 1 END) AS AHT 
FROM    reporting_call_matrix AS A WITH (NOLOCK) 
WHERE  A.CALENDAR_DATE >= '10/01/2015' AND A.CALENDAR_DATE <= '9/30/2016' AND A.SPLIT IN (9,26,23,43,48,33,56,70,71,72,74,50) AND ( A.ent_split IS NOT NULL)
Group BY A.SPLIT, A.CALENDAR_DATE

需要分解成白天。现在它已经卷入了几个月

1 个答案: