Question

我对Python中的正则表达式有疑问。

可能的变化可能是

10小时，12周或7个工作日。

我想让我的正则表达式像

string = "I have an 7 business day trip and 12 weeks vacation."
re.findall(r'\d+\s(business)?\s(hours|weeks|days)', string)

所以我希望找到＆＃34; 7个工作日＆＃34;和＆＃34; 12周＆＃34;但它返回无

Answer 1

string = "I have an 7 business day trip and 12 weeks vacation."
print re.findall(r'\d+\s(?:business\s)?(?:hour|week|day)s?', string)
['7 business day', '12 weeks']

\d+\s(?:business\s)?(?:hour|week|day)s?

Debuggex Demo

演示应该解释这是如何工作的。你的原因不是因为它正在寻找不匹配的7 businessdays。

虽然如果您不想接受business week/hour，则需要进一步修改：

\d+\s(?:hour|week|(?:business )?day)s?

Debuggex Demo

Answer 2

你需要调整你的正则表达式：

>>> string = "I have an 7 business day trip and 12 weeks vacation."
>>> print re.findall(r'(\d+)\s*(?:business day|hour|week)s?', string)
['7', '12']

这与最后跟business day或hour或week以及可选s的任何数字相匹配。

Answer 3

与@ anubhava的答案相似，但匹配＆＃34; 7个工作日＆＃34;而不只是＆＃34; 7＆＃34;。只需将右括号从\ d +后移到结尾：

re.findall(r'(\d+\s*(?:business day|hour|week)s?)', string)

Answer 4

\ d + \ S +（商业\ S）（小时|一周|天）？？的

正则表达式匹配Python中的几个字符串

4 个答案: