MongoDB聚合始终返回0值

时间:2016-10-18 16:11:04

标签: javascript json mongodb mongodb-query aggregation-framework

以下查询:

[{
            $match: {
                $and: [
                    {campaignID: "12345"},
                    {date: "2016-10-18"},
                    {hour: {$gte: 0}},
                    {hour: {$lte: 3}}
                ]
            }
        }
}]

返回以下(正确)数据:

[{"_id":"580638b1e4b01c1a027e82c1","campaignID":"12345","date":"2016-10-18",
"hour":0,"foo":10,"bar":10},
{"_id":"580638cbe4b01c1a027e82c2","campaignID":"12345","date":"2016-10-18",
"hour":1,"foo":11,"bar":11},
{"_id":"580638e5e4b01c1a027e82c3","campaignID":"12345","date":"2016-10-18",
"hour":2,"foo":12,"bar":12},
{"_id":"580638efe4b01c1a027e82c4","campaignID":"12345","date":"2016-10-18",
"hour":3,"foo":13,"bar":13}]

但是以下查询:

[
        {
            $match: {
                $and: [
                    {campaignID: "12345"},
                    {date: "2016-10-18"},
                    {hour: {$gte: 0}},
                    {hour: {$lte: 3}}
                ]
            }
        },
        {
            $group: {
                _id: campaignID,
                foo:{$sum: "foo"},
                bar:{$sum: "bar"}
            }
        }
]

返回以下(错误)数据:

[{"_id":"sA48VsoQyuuEDVI5lr4loL31mqoCRT","foo":0,"bar":0}]

两个' foo'和' bar'应该是46(10 + 11 + 12 + 13)

我做错了什么?

1 个答案:

答案 0 :(得分:3)

您应该使用带字段名称的$来引用其值。

$group: {
    _id: "$campaignID",
    foo:{$sum: "$foo"},
    bar:{$sum: "$bar"}
}