Question

for ($img=0;$img<=5;$img++)
{
    if (!empty($_FILES['picture_add_'.$img]))
    {
        if ($this->upload->do_upload('picture_add_'.$img))
        {
            $uploaded = $this->upload->data();
            $data_picture_add = array(
                                    'filename'  => $uploaded['file_name'],
                                    'id'        => $last_id
                                    );
            $this->db->insert('db_picture_individual', $data_picture_add);
        }
    }
}

如果我输入2个或更多的文件图片，我只会加密一个文件名。

如何加密所有文件名？

这是观点：

<input name="picture_add_1" class="form-control" style="padding-top: 0;" type="file">
<input name="picture_add_2" class="form-control" style="padding-top: 0;" type="file">
<input name="picture_add_3" class="form-control" style="padding-top: 0;" type="file">
<input name="picture_add_4" class="form-control" style="padding-top: 0;" type="file">
<input name="picture_add_5" class="form-control" style="padding-top: 0;" type="file">

Answer 1

尝试在循环语句中使用config。

        for ($i = 1; $i <= count($_FILES); $i++) {
           $config = array();
           $config['upload_path'] = './media/project_files';
           $config['allowed_types'] = '*';
           $config['max_size'] = '51200';
           $config['max_width'] = '5000';
           $config['max_height'] = '5000';
           $config['remove_spaces'] = TRUE;
           $config['encrypt_name'] = TRUE;

            $ups = $this->upload->do_upload("upload_file$i");
            $imgName[$i] = $this->upload->data();
        }

如何在循环中获取文件名加密文件上传codeigniter

1 个答案: