Question

长话短说。我的应用程序启动时，我想从互联网上下载一些谷歌表文件。情况如下：

较新的设备：一切正常，无问题，所有文件都已下载。

旧设备（API 16-17）：正确下载第一个工作表文件。 无法下载第二个文件。我收到 HTTP / 1.1 302暂时移动问题，文件无法正确下载。

我为这两个文件调用了AsynchTask。 AsynchTask运行完美，我尝试了其他方法来查看AsynchTask是否存在问题。此外，所有链接都非常精细且有效。

这是我的AsynchTask类代码的一部分：

下载文件的方法：

private String downloadUrl(String urlString) throws IOException {
    InputStream is = null;

    try {
        URL url = new URL(urlString);
        HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
        conn.setInstanceFollowRedirects(true);  //you still need to handle redirect manully.
        HttpsURLConnection.setFollowRedirects(true);
        conn.setReadTimeout(10000 /* milliseconds */);
        conn.setConnectTimeout(15000 /* milliseconds */);
        conn.setInstanceFollowRedirects(true);
        conn.setRequestMethod("GET");
        conn.setDoInput(true);
        // Starts the query
        conn.connect();
        int responseCode = conn.getResponseCode();
        is = conn.getInputStream();

        String contentAsString = convertStreamToString(is);
        Log.d("contentAsString",contentAsString);
        return contentAsString;
    } finally {
        if (is != null) {
            is.close();
        }
    }
}

字符串结果（HTTP / 1.1 302 Moved Temporarily message）

 HTTP/1.1 302 Moved Temporarily
      Content-Type: text/html; charset=UTF-8
      Cache-Control: no-cache, no-store, max-age=0, must-revalidate
      Pragma: no-cache
      Expires: Mon, 01 Jan 1990 00:00:00 GMT
      Date: Tue, 18 Oct 2016 09:26:14 GMT
      Location: https://docs.google.com/spreadsheets/d/1hRiDvdLPkQEdTSVxmWEoWXjmCFQodNjMNYi3Fd7yYn0/gviz/tq
      P3P: CP="This is not a P3P policy! See https://support.google.com/accounts/answer/151657?hl=en for more info."
      P3P: CP="This is not a P3P policy! See https://support.google.com/accounts/answer/151657?hl=en for more info."
      Content-Encoding: gzip
      X-Content-Type-Options: nosniff
      X-XSS-Protection: 1; mode=block
      Server: GSE
      Set-Cookie: NID=89=afVN4Sa74ZsYuffxNSiXn2wWTJkSUULbtZperbpr8T9hPzHoFzx-uGu_lJUVCkYSd1eZUPUFucffCDHc7lPConnfPpTMbqAOgIcIQoJG6TQFUHzBUNW6bFqUy__ZthsR;Domain=.google.com;Path=/;Expires=Wed, 19-Apr-2017 09:26:14 GMT;HttpOnly
      Set-Cookie: NID=89=k5r33ZLA4l__4v1CE1iGrtQbtqoJxOyVxwrSMbsKWviK74u-vM32WdKtt-txFEOhPWo1g9f1CWMXcu6Fuczo4ZCck47D23tIZZRcqpRxkSB0z5w2xI9oj1Jcq8duISiU;Domain=.google.com;Path=/;Expires=Wed, 19-Apr-2017 09:26:14 GMT;HttpOnly
      Alt-Svc: quic=":443"; ma=2592000; v="36,35,34,33,32"
      Transfer-Encoding: chunked

      00000001
      
      00000001
      �
      00000001
      
      00000001
      ��
      00000001
      ��
      00000001
      ��
      00000001
      ��
      00000001
      ��
      00000001
      ��
      00000001
      ��
      00000001
      m
      00dc
      ��N�0D��
      �ܳ�8 !7R�8)ih�hs��U�R�!6��q
      G����HoY!�2�X����,J�TfFI��L�4��~����Z�~��eݬ�]D����E��.�k�n$i��/���r,%E��U΍��gl�ӟ1>
      v���V!:���Y�/�;.��ۗ�s�?��&��=U�v���õ�,���op4Q8!�4�=�
      %��O����ڛ�����
      0

在阅读了一下有关HTTP 302之后，我知道我必须以某种方式重定向。问题是我不知道该怎么做。此外，我不知道为什么这个问题只出现在较旧的Android版本上。

我现在已经挣扎了一个星期。任何反馈意见！谢谢！

Answer 1

关注重定向的关键是按键location取标题，然后将其用作您的网址：

Location: https://docs.google.com/spreadsheets/d/1hRiDvdLPkQEdTSVxmWEoWXjmCFQodNjMNYi3Fd7yYn0/gviz/tq

这只是网络服务器的说法＆＃34;嘿，你的页面移到了这里。转而去！＆＃34;。

这个article by mkyong.com有一个很好的例子：

package com.mkyong.http;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

public class HttpRedirectExample {
    public static void main(String[] args) {
        try {
            String url = "http://www.twitter.com";

            URL obj = new URL(url);
            HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
            conn.setReadTimeout(5000);
            conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
            conn.addRequestProperty("User-Agent", "Mozilla");
            conn.addRequestProperty("Referer", "google.com");

            System.out.println("Request URL ... " + url);

            boolean redirect = false;

            // normally, 3xx is redirect
            int status = conn.getResponseCode();
            if (status != HttpURLConnection.HTTP_OK) {
                if (status == HttpURLConnection.HTTP_MOVED_TEMP
                || status == HttpURLConnection.HTTP_MOVED_PERM
                || status == HttpURLConnection.HTTP_SEE_OTHER)
                    redirect = true;
            }

            System.out.println("Response Code ... " + status);

            if (redirect) {
                // get redirect url from "location" header field
                String newUrl = conn.getHeaderField("Location");

                // get the cookie if need, for login
                String cookies = conn.getHeaderField("Set-Cookie");

                // open the new connnection again
                conn = (HttpURLConnection) new URL(newUrl).openConnection();
                conn.setRequestProperty("Cookie", cookies);
                conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
                conn.addRequestProperty("User-Agent", "Mozilla");
                conn.addRequestProperty("Referer", "google.com");

                System.out.println("Redirect to URL : " + newUrl);
            }

            BufferedReader in = new BufferedReader(
            new InputStreamReader(conn.getInputStream()));
            String inputLine;
            StringBuffer html = new StringBuffer();

            while ((inputLine = in.readLine()) != null) {
                html.append(inputLine);
            }
            in.close();

            System.out.println("URL Content... \n" + html.toString());
            System.out.println("Done");
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

HTTP / 1.1 302暂时移动 - 在Android API 16-17上发生

1 个答案: