Question

我有一个zend教程zip，但是当我运行它时，我收到两个警告，列在下面

Warning: include(/var/www/html/zendapp/module/Admin/config/../view/layout/layout.phtml): failed to open stream: No such file or directory in /var/www/html/zendapp/vendor/zendframework/zendframework/library/Zend/View/Renderer/PhpRenderer.php on line 506


Warning: include(): Failed opening '/var/www/html/zendapp/module/Admin/config/../view/layout/layout.phtml' for inclusion (include_path='.:/usr/share/php:/usr/share/pear') in /var/www/html/zendapp/vendor/zendframework/zendframework/library/Zend/View/Renderer/PhpRenderer.php on line 506

请帮帮我，我试过谷歌，但仍无法找到任何解决方案。

我在Admin/config/module/module.config.php中获得了＆＃39; template_map＆＃39;有

的数组

'view_manager' => array(
        'display_not_found_reason' => true,
        'display_exceptions'       => true,
        'doctype'                  => 'HTML5',
        'not_found_template'       => 'error/404',
        'exception_template'       => 'error/index',
        'template_map' => array(
            'layout/layout'           => __DIR__ . '/../view/layout/layout.phtml',
            'application/index/index' => __DIR__ . '/../view/application/index/index.phtml',
            'error/404'               => __DIR__ . '/../view/error/404.phtml',
            'error/index'             => __DIR__ . '/../view/error/index.phtml',
        ),
        'template_path_stack' => array(
            'admin' => __DIR__ . '/../view'
        ),
    ),

并且layout.phtml的位置为var/www/html/zendapp/module/Application/view/layout/layout.phtml

为什么我用zend框架获取include_path警告？

0 个答案: