Question

我目前正在尝试计算一个文章类别在故障单表格中出现的次数问题是类别有子类别，它们都在表格中列为单个字符串（“Cat1＆gt; Subcat1”，“Cat1＆gt; Subcat2”等）。

我到目前为止所做的工作是设法列出所有不同的类别，但我想从结果中删除任何子类别并合并任何副本。

例如，我有以下类别和计数：

类别| 13个
  分类＆gt; Subcat1 | 14个
  分类＆gt; Subcat2 | 3

我想看到的是：

类别| 30

到目前为止，我已设法剥离子类别，但实际行基本上是重复的，具有不同的值：

类别| 13个
类别| 14 类别| 3

这是我目前的代码：

SELECT 
CASE
    WHEN CHARINDEX(' >',SUBSTRING(KM2.GENERATEDCATS,16,20))=0 
    THEN SUBSTRING(KM2.GENERATEDCATS,16,20) 
    ELSE SUBSTRING(SUBSTRING(KM2.GENERATEDCATS,16,20),1,CHARINDEX(' >',SUBSTRING(KM2.GENERATEDCATS,16,20)))
END AS "Final",
COUNT(KM2.GENERATEDCATS) AS "Count"

FROM INCIDENTSM1 AS SD LEFT JOIN KMDOCUMENTM1 AS KM1 ON SD.CBA_KPF_ID=KM1.ID
LEFT JOIN KMDOCUMENTA2 AS KM2 ON KM1.ID=KM2.ID
GROUP BY KM2.GENERATEDCATS
ORDER BY Count DESC

传奇：

INCIDENTSM1 - 售票表
  KMDOCUMENTM1 - 物品表
  KMDOCUMENTA2 - 类别（与主表分开）
  GENERATEDCATS - 类别列

是否可以将所有这些“类别”行合并为一个总计数？

Answer 1

尝试GROUP BY提取的类别名称：

SELECT CASE
          WHEN CHARINDEX(' >',SUBSTRING(KM2.GENERATEDCATS,16,20))=0 
          THEN SUBSTRING(KM2.GENERATEDCATS,16,20) 
          ELSE SUBSTRING(SUBSTRING(KM2.GENERATEDCATS,16,20),1,
                         CHARINDEX(' >',SUBSTRING(KM2.GENERATEDCATS,16,20)))
       END AS "Final",
COUNT(KM2.GENERATEDCATS) AS "Count"    
FROM INCIDENTSM1 AS SD 
LEFT JOIN KMDOCUMENTM1 AS KM1 ON SD.CBA_KPF_ID=KM1.ID
LEFT JOIN KMDOCUMENTA2 AS KM2 ON KM1.ID=KM2.ID
GROUP BY CASE
            WHEN CHARINDEX(' >',SUBSTRING(KM2.GENERATEDCATS,16,20))=0 
            THEN SUBSTRING(KM2.GENERATEDCATS,16,20) 
            ELSE SUBSTRING(SUBSTRING(KM2.GENERATEDCATS,16,20),1,CHARINDEX(' >',
                           SUBSTRING(KM2.GENERATEDCATS,16,20)))
         END
ORDER BY Count DESC

将行组合为重复值

1 个答案: