我有一个ArrayList<对象>其中Object是我所创建的类的实例。我想将这个新的数组列表传递回主活动,将其放入导航条项目中。
如何传递ArrayList<对象>从活动回到主要活动?
我已经尝试过bundle.getParcelableArrayList但它告诉我“类型参数T的推断类型对象不在其范围内,应该实现android.os.parcelable”
这是我的代码:
public void createPlaylist(String playlistName, ArrayList<Song> newPlaylistSongsArray) {
Intent returnIntent = new Intent();
Bundle b = new Bundle();
b.putParcelableArrayList("array", (ArrayList<? extends Parcelable>) newPlaylistSongsArray);
returnIntent.putExtra("playListName", playlistName);
returnIntent.putExtra("array", newPlaylistSongsArray);
setResult(Activity.RESULT_OK,returnIntent);
finish();
}
和
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == 1) {
if (resultCode == Activity.RESULT_OK){
String newPlaylistName = data.getStringExtra("playListName");
Bundle b = getIntent().getExtras();
final ArrayList<Song> newPlaylist = b.getParcelableArrayList("array");
Toast.makeText(MP3Player.this, "New Playlist Created", Toast.LENGTH_LONG).show();
}
if (resultCode == Activity.RESULT_CANCELED) {
Toast.makeText(MP3Player.this, "Shit went wrong yo!", Toast.LENGTH_LONG).show();
}
}
}
答案 0 :(得分:2)
最简单的方法是,您的Song类需要实现Serializable。
Bundle bundle = new Bundle();
bundle.putSerializable("newPlaylist", newPlaylist);
intent.putExtras(bundle);
在其他活动中:
Intent intent = this.getIntent();
Bundle bundle = intent.getExtras();
ArrayList<Song> newPlaylist=
(ArrayList<Song>)bundle.getSerializable("newPlaylist");