Question

我正在尝试将以下JSON字符串发送到Java中的url：

标签名称为data且正文为

{"process": "mobileS","phone": "9999999999"}

到目前为止我的代码如下：

HttpClient httpClient = HttpClientBuilder.create().build(); //Use this instead

try {
    HttpPost request = new HttpPost("url goes here");
    StringEntity params = new StringEntity("details={\"process\":\"mobileS\",\"phone\":\"9999999999\"}");
    request.addHeader("content-type", "application/x-www-form-urlencoded");
    request.setEntity(params);

    HttpResponse response = httpClient.execute(request);
    System.out.println(response);

    // handle response here...
} catch (Exception ex) {
    // handle exception here
} finally {
    httpClient.getConnectionManager().shutdown(); //Deprecated
}

我应该在将JSON数据发送到服务器后从上面获取JSON字符串，但在发送上述请求后我不知道该去哪里。

好处是响应会返回200响应并显示通常来自HttpResponse结果的所有其他信息，但我得到的结果类似于：

{"test": {"this is":"what I am supposed to get"}}

所以基本上它应该返回一个JSON字符串，我得到的东西与我需要的东西完全不同

HttpResponseProxy{HTTP/1.1 200 OK [Cache-Control: no-store, no-cache, must-revalidate, max-age=0,post-check=0, pre-check=0 etc etc etc

我似乎无法理解我做错了什么。

Answer 1

HttpResponse类公开了getEntity方法，该方法返回HttpEntity个实例。这提供了一种访问响应内容的机制。

您可以使用EntityUtils来检索和使用实体的内容流：

private void getData(){
    CloseableHttpClient httpClient = HttpClientBuilder.create().build(); //Use this instead
    CloseableHttpResponse response = null;
    HttpEntity entity = null;

    try {
        HttpPost request = new HttpPost("url goes here");
        StringEntity params = new StringEntity("details={\"process\":\"mobileS\",\"phone\":\"9999999999\"}");
        request.addHeader("content-type", "application/x-www-form-urlencoded");
        request.setEntity(params);

        response = httpClient.execute(request);
        System.out.println(response);

        // handle response here...
        if (successful(response)) {
            entity = response.getEntity();
            String content = EntityUtils.toString(entity);

            System.out.println(content);
        }
    } catch (Exception ex) {
        // handle exception here
    } finally {
        EntityUtils.consumeQuietly(entity);
        if (response != null) response.close();
        if (httpClient != null) httpClient.close();
    }
}

// TODO Customize for your server/interaction
private boolean successful(HttpResponse response) {
    return response != null 
            && response.getStatusLine() != null 
            && response.getStatusLine().getStatusCode() == 200;
}

将JSON发送到Java post并显示信息

1 个答案: