Question

我正在删除Slack中的幻像文件。下面是我的脚本。我得到一个IndexError列表索引超出范围错误。有人可以帮我解决我的错误。

import Slacker
import sys
import time
from datetime import timedelta, datetime


def main(token, weeks=4):
    slack = Slacker(token)
    total = slack.files.list(count=1).body['paging']['total']
    num_pages = int(total/1000.00 + 1)
    print("{} files to be processed, across {} pages".format(total, num_pages))
    files_to_delete = []
    ids = [] 
    count = 1
    for page in range(num_pages):
        print ("Pulling page number {}".format(page + 1))
        files = slack.files.list(count=1000, page=page+1).body['files']
        for file in files:
            print("Checking file number {}".format(count))
            if file['id'] not in ids:
                ids.append(file['id'])
                if datetime.fromtimestamp(file['timestamp']) < datetime.now() - timedelta(weeks=weeks):
                    files_to_delete.append(file)
                    print("File No. {} will be deleted".format(count))
                else:
                    print ("File No. {} will not be deleted".format(count))
            count+=1

    print("All files checked\nProceeding to delete files")
    print("{} files will be deleted!".format(len(files_to_delete)))
    count = 1
    for file in files_to_delete:
        print("Deleting file {} of {}".format(count, len(files_to_delete)))
        slack.files.delete(file_=file['id'])
        print("Deleted Successfully")
        count+=1

    return count-1

if __name__ == "__main__":
    try:
        token = sys.argv[1:]
    except IndexError:
        print("Usage: python file_deleter.py api_token\nPlease provide a value for the API Token")
        sys.exit(2)

    main(token[0])

它在最后一行main（token [0]）上给出错误。

Traceback (most recent call last):
  File "C:/Users/aqureshi/Desktop/Programming/Slacker.py", line 50, in <module>
    main(token[0])
IndexError: list index out of range

Answer 1

名义上你可以通过在try / except块中移动main(token[0])来解决问题。但这是有问题的，因为程序中的任何其他IndexError都可能被错误地报告为命令使用问题。最好明确检查输入参数。它还为您提供了检查常见帮助标记的机会。

if __name__ == "__main__":
    if len(sys.argv) != 2 or sys.argv[1] in ('-h', '--help', '/?'):
        print("Usage: python file_deleter.py api_token\nPlease provide a value for the API Token")
        sys.exit(2)
    main(sys.argv[1])

Answer 2

您可以像这样解决错误，但这只是告诉您如何实际运行此文件。

换句话说，请提供API令牌的值

if __name__ == "__main__":
    try:
        token = sys.argv[1:]
        main(token[0])
    except IndexError:
        print("Usage: python file_deleter.py api_token\nPlease provide a value for the API Token")
        sys.exit(2)

像Desktop\> python Slacker.py xxxxAPI_TOKENxxxx

这样的东西

我可能会重写那个尝试 - 除了实际验证参数的长度，但是

if __name__ == "__main__":
    if len(sys.argv) != 2:
        print("Usage: python file_deleter.py api_token\nPlease provide a value for the API Token")
        sys.exit(2)

    token = sys.argv[1:]
    main(token[0])

Answer 3

期待这个

token = sys.argv[1:]

抛出异常是错误的。它永远不会，如果sys.argv本身只有长度1，它将继续返回一个空列表。然后

main(token[0])

是你的IndexError

而是检查sys.argv变量的长度。有一个或多个参数应该至少为2。

import sys

def main(x):
    print(x)

if __name__ == "__main__":

    if len(sys.argv) < 2:
        print("Usage: python file_deleter.py api_token\nPlease provide a value for the API Token")
        sys.exit(2)

    main(sys.argv[1])

IndexError错误错误Python

3 个答案: