Question

我正在编写一个函数来计算带有where条件的null列，但是这个函数存在问题

process.env.DATABASE_URI

此功能进行了查询

protected function _get_mcq_attept_count2( $mcq_id){
    $this->load->model('museranswer');  
    return $this->museranswe>count_by(array('mcq_id'=>$mcq_id,'bookrefrence!='=>" "));
}

此查询返回空列值

Answer 1

像array("mcq_id" => "$mcq_id", "bookrefr‌ence IS NOT NULL" => null)一样更改您的查询。希望你能得到正确的答案。如果它不起作用，请与我们分享您的模型。

Answer 2

I hope this code work for it bcz in code-igniter i always use like this .

 protected function _get_mcq_attept_count2($mcq_id)
    {
        $this->load->model('museranswer');  
        $where = array('mcq_id'=>$mcq_id);
        return $this->museranswe>count_by($where);
    }

    /******************* FOR MODEL *********************/

    public function count_by($where)
    {
        $this->db->select('count(mcq_id) as numrows');
        $this->db->from('user_answer');
        $this->db->where($where);
        $this->db->where('bookrefrence !=',' ');

        $qry = $this->db->get();
        return $qry->result_array();
    }

Answer 3

返回$ this-＆gt; museranswer-＆gt; count_by（array（'mcq_id'=＆gt; $ mcq_id，'length（bookrefrence）＆gt; 2'））;

使用codeigniter中的where where计算非null值

3 个答案: