我正在编写一个程序，它会提示用户输入temp作为整数，然后提示用户选择temp所在的比例，华氏度，摄氏度或开尔文。然后它会提示用户从3个刻度选项中选择要转换为的温度，然后计算转换并显示最终温度。我的程序目前运行但运行不正确，我已经盯着这几天了，我不知道它为什么要编译它的方式。我仍然是一个相当新的编码，这是一个我一直在寻找一些建议的课程作业。
封装tempconverter; import java.util。*;
公共类TempConverter {
public static void main(String[] args)
{
double temp1;
double convertTo;
double finalTemp;
double currScale;
char cont='E';
char process='P';
int scale1=0;
int scale2=0;
do
{
//input
getTemp();
scaleOne(scale1);
toScale(scale2);
//process
System.out.print("Your final temp is: " +convert()+toScale(scale2));
}while(cont=='N');
}
private static double getTemp()
{
double temp;
double currentTemp;
Scanner userIn= new Scanner(System.in);
System.out.print("Enter a temperature to convert ");
while(!userIn.hasNextDouble())
{
System.out.println("That is not a valid temperature!");
System.out.print("Re-enter a temperature: ");
userIn.next();
}
temp=userIn.nextDouble();
return temp;
}
private static String scaleOne(int userChoice)
{
Scanner userIn= new Scanner(System.in);
System.out.print("What scale is your temp currently in?"+
"1: Fahrenheit" +
"2: Celsius" +
"3: Kelvin" +
"Please enter 1, 2, or 3: ");
String scale="";
switch(userChoice)
{
case 1:
{scale= "Fahrenheit";
break;}
case 2:
{scale="Celsius";
break;}
case 3:
{scale="Kelvin";
break;}
default:
{scale= "There was an error in your choice!";}
}
return scale;
}
private static String toScale(int userChoice)
{
Scanner userIn= new Scanner(System.in);
System.out.print("What scale would you like to convert to?"+
"1: Fahrenheit" +
"2: Celsius" +
"3: Kelvin" +
"Please enter 1, 2, or 3: ");
String scale2="";
switch(userChoice)
{
case 1:
{scale2= "Fahrenheit";
break;}
case 2:
{scale2="Celsius";
break;}
case 3:
{scale2="Kelvin";
break;}
default:
{scale2= "There was an error in your choice!";}
}
return scale2;
}
public static double convert()
{
double farToKel;
double farToCel;
double celToKel;
double celToFar;
double kelToFar;
double kelToCel;
int scale1=0;
double converts;
if(scaleOne(scale1)=="Fahrenheit" && toScale(scale1)=="Kelvin")
{
converts=farToKel=(getTemp()+459.67)* 5/9;
}
else if(scaleOne(scale1)=="Fahrenheit" && toScale(scale1)=="Celsius")
{
converts=farToCel=(getTemp()-32)*5/9;
}
else if(scaleOne(scale1)=="Celsius" && toScale(scale1)=="Kelvin")
{
converts=celToKel=getTemp()+273.15;
}
else if(scaleOne(scale1)=="Celsius" && toScale(scale1)=="Fahrenheit")
{
converts=celToFar=getTemp()*9/5+32;
}
else if(scaleOne(scale1)=="Kelvin" && toScale(scale1)=="Fahrenheit")
{
converts=kelToFar=getTemp()*9/5-459.67;
}
else
{
converts=kelToCel=getTemp()-276.15;
}
return converts;
}
}
这就是它编译的内容
运行： 输入要转换100的温度 你的气温目前是多少？1：华氏2：摄氏3：开尔文请输入1,2或3：你要转换成什么尺度？1：华氏2：摄氏3：开尔文请输入1,2或3：什么尺度是你的临时状态是什么？1：华氏温度2：摄氏度3：开尔文请输入1,2或3：你的温度目前是多少？1：华氏温度2：摄氏温度3：开尔文请输入1,2或3：你的温度目前是多少？1：华氏温度2：摄氏度3：开尔文请输入1,2或3：你当前的温度是多少？1：华氏温度2：摄氏温度3：开尔文请输入1,2或3：你的温度目前是多少？1：华氏温度2 ：Celsius3：Kelvin请输入1,2或3：输入要转换的温度2 你希望转换成什么尺度？1：华氏2：摄氏3：开尔文请输入1,2或3：你的最终温度是：-274.15你选择的错误！建立成功（总时间：33秒）
它似乎没有按照正确的顺序进行编译，或者以正确的顺序获取正确的信息并一遍又一遍地获取一些信息。输入数字温度后，它会提示您输入刻度，但不会只是一次打印出来，然后您输入第一个刻度的选择，它就会一直完成而无需您输入选择toScale。
答案 0 :(得分：3)
请参阅下面的代码中插入的注释和更正。
public class TempConverter {
// variables that are needed in more than one method must be declared outside the methods
// (static since the methods are static; not recommended, but let it be for now)
static double temp1;
static String scale1;
static String scale2;
public static void main(String[] args) {
// get rid of unused variables
char cont = 'E';
do {
// input
// save all inputs to variables
temp1 = getTemp();
// Java parameters are pass by value, so to get a value out of the method, use the returned value
// then you don’t need the parameter
scale1 = scaleOne();
scale2 = toScale();
// process
// don’t call toScale() again, or the user will be prompted again,
// instead, use the value already stored in scale2
System.out.print("Your final temp is: " + convert() + ' ' + scale2);
// you should set cont to something if you want the loop to repeat
} while (cont == 'N');
}
private static double getTemp() {
double temp;
Scanner userIn = new Scanner(System.in);
System.out.print("Enter a temperature to convert ");
while (!userIn.hasNextDouble()) {
System.out.println("That is not a valid temperature!");
System.out.print("Re-enter a temperature: ");
userIn.next();
}
temp = userIn.nextDouble();
return temp;
}
private static String scaleOne() {
Scanner userIn = new Scanner(System.in);
// \n is a line break for readability
System.out.print("What scale is your temp currently in?"
+ "\n1: Fahrenheit"
+ "\n2: Celsius"
+ "\n3: Kelvin"
+ "\nPlease enter 1, 2, or 3: ");
// read a value from the user
int userChoice = userIn.nextInt();
String scale = "";
switch (userChoice) {
case 1: {
scale = "Fahrenheit";
break;
}
case 2: {
scale = "Celsius";
break;
}
case 3: {
scale = "Kelvin";
break;
}
default: {
scale = "There was an error in your choice!";
}
}
return scale;
}
private static String toScale() {
Scanner userIn = new Scanner(System.in);
System.out.print("What scale would you like to convert to?" + "1: Fahrenheit" + "2: Celsius" + "3: Kelvin"
+ "Please enter 1, 2, or 3: ");
String scale2 = "";
int userChoice = userIn.nextInt();
// ideally should not accept the same scale as scale1 (from scale)
switch (userChoice) {
case 1: {
scale2 = "Fahrenheit";
break;
}
case 2: {
scale2 = "Celsius";
break;
}
case 3: {
scale2 = "Kelvin";
break;
}
default: {
scale2 = "There was an error in your choice!";
}
}
return scale2;
}
public static double convert() {
// need only one variable for result
double converts;
// don’t call methods again, use variables
// don’t use == for comparing strings, use .equals
// typo: the second scale corrected to scale2
if (scale1.equals("Fahrenheit") && scale2.equals("Kelvin")) {
// don’t call getTemp() again
converts = (temp1 + 459.67) * 5 / 9;
}
else if (scale1.equals("Fahrenheit") && scale2.equals("Celsius")) {
converts = (temp1 - 32) * 5 / 9;
}
else if (scale1.equals("Celsius") && scale2.equals("Kelvin")) {
converts = temp1 + 273.15;
}
else if (scale1.equals("Celsius") && scale2.equals("Fahrenheit")) {
converts = temp1 * 9 / 5 + 32;
}
else if (scale1.equals("Kelvin") && scale2.equals("Fahrenheit")) {
converts = temp1 * 9 / 5 - 459.67;
}
else { // Kelvin to Celsius
converts = temp1 - 276.15;
}
return converts;
}
}
我相信它现在基本上有用了。
答案 1 :(得分：1)
public static void main(String[] args)
{
String scaleOne;
String scaleTwo;
System.out.println("What scale is your temp currently in?\n"+
"1: Fahrenheit\n" +
"2: Celsius\n" +
"3: Kelvin\n" +
"Please enter 1, 2, or 3: \n");
scaleOne = getScale();
System.out.println("What scale would you like to convert to?\n"+
"1: Fahrenheit\n" +
"2: Celsius\n" +
"3: Kelvin\n" +
"Please enter 1, 2, or 3:\n ");
scaleTwo = getScale();
System.out.print("Your final temp is: " +convert(scaleOne,scaleTwo));
}
private static double getTemp()
{
double temp;
Scanner userIn= new Scanner(System.in);
System.out.print("Enter a temperature to convert ");
while(!userIn.hasNextDouble())
{
System.out.println("That is not a valid temperature!");
System.out.println("Re-enter a temperature: ");
userIn.next();
}
temp=userIn.nextDouble();
return temp;
}
private static String getScale()
{
Scanner userIn= new Scanner(System.in);
String scale="";
switch(userIn.nextInt())
{
case 1:
scale= "Fahrenheit";
break;
case 2:
scale="Celsius";
break;
case 3:
scale="Kelvin";
break;
default:
scale= "There was an error in your choice!";
}
return scale;
}
相应地更改主函数以及scaleone（）和toScale（）函数。您的代码存在许多无法单独解决的问题。请随时询问有关答案的任何说明
答案 2 :(得分：1)
你必须相信编译器正确地完成它的工作。错误在于你的逻辑。我假设您正在尝试创建一个程序，将温度从3种格式转换为其他格式。
在调用scaleOne(scale1);方法时，您提供了一个硬编码值0作为参数，并且从未在方法内部进行更改。同时你试图从用户那里获得输入。要获取用户输入，您需要在方法正文中添加int userChoice = userIn.nextInt();。
这将返回一个sting值，您需要将其存储在main方法的sacle1变量中。
类似于toScale()方法，您需要使其非参数化并从用户内部方法中获取输入。
这将再次返回一个sting值，您需要将其存储在main方法的sacle2变量中。
现在，在调用转换方法时，您需要传递scale1和scale2作为参数。我不明白在每个if条件下再次调用scaleOne()和toScale()方法的逻辑是什么。这是您的代码一次又一次地要求选择温度类型的原因。我在解决方案中使用scale1和scale2变量删除了它们。
永远记住，永远不要使用==运算符进行String比较。始终使用字符串类的equals()或equalsEgnoreCase()方法。
我已对您的代码进行了更改，并尝试根据需要获得更具体的解决方案。希望这会有所帮助。不要忘了投票。
public class TempConverter {
public static void main(String[] args)
{
String scale1;
String scale2;
//input
scale1 =scaleOne();
scale2 = toScale();
//process
System.out.print("Your final temp is: " +convert(scale1, scale2));
}
private static double getTemp()
{
double temp;
Scanner userIn= new Scanner(System.in);
System.out.print("Enter a temperature to convert ");
while(!userIn.hasNextDouble())
{
System.out.println("That is not a valid temperature!");
System.out.print("Re-enter a temperature: ");
userIn.next();
}
temp=userIn.nextDouble();
return temp;
}
private static String scaleOne() {
Scanner userIn= new Scanner(System.in);
System.out.print("What scale is your temp currently in?"+
"1: Fahrenheit" +
"2: Celsius" +
"3: Kelvin" +
"Please enter 1, 2, or 3: ");
int userChoice = userIn.nextInt();
String scale="";
switch(userChoice)
{
case 1:
{scale= "Fahrenheit";
break;}
case 2:
{scale="Celsius";
break;}
case 3:
{scale="Kelvin";
break;}
default:
{scale= "There was an error in your choice!";}
}
return scale;
}
private static String toScale(){
Scanner userIn= new Scanner(System.in);
System.out.print("What scale would you like to convert to?"+
"1: Fahrenheit" +
"2: Celsius" +
"3: Kelvin" +
"Please enter 1, 2, or 3: ");
String scale2="";
int userChoice = userIn.nextInt();
switch(userChoice)
{
case 1:
{scale2= "Fahrenheit";
break;}
case 2:
{scale2="Celsius";
break;}
case 3:
{scale2="Kelvin";
break;}
default:
{scale2= "There was an error in your choice!";}
}
return scale2;
}
public static double convert(String scale1, String scale2)
{
double converts;
if(scale1.equalsIgnoreCase("Fahrenheit") && scale2.equalsIgnoreCase("Kelvin"))
{
converts=(getTemp()+459.67)* 5/9;
}
else if(scale1.equalsIgnoreCase("Fahrenheit") && scale2.equalsIgnoreCase("Celsius"))
{
converts=(getTemp()-32)*5/9;
}
else if(scale1.equalsIgnoreCase("Celsius") && scale2.equalsIgnoreCase("Kelvin"))
{
converts=getTemp()+273.15;
}
else if(scale1.equalsIgnoreCase("Celsius") && scale2.equalsIgnoreCase("Fahrenheit"))
{
converts=getTemp()*9/5+32;
}
else if(scale1.equalsIgnoreCase("Kelvin") && scale1.equalsIgnoreCase("Fahrenheit"))
{
converts=getTemp()*9/5-459.67;
}
else
{
converts=getTemp()-276.15;
}
return converts;
}}
答案 3 :(得分：1)
毕竟说完了，我完成了它，并且按照课堂要求正确运行。感谢所有的反馈！
package tempconverter;
import java.util.Scanner;
public class TempConverter
{
static double temp1;
static String scale1;
static String scale2;
static double conv;
public static void main(String[] args)
{
char cont='N';
do
{ menueOne();
menueCatch();
cont=contOption();
}while(cont=='Y');
}
private static void menueOne()
{
System.out.print("Please make a selection."
+"\n1: Begin"
+"\n2: Exit"
+"\n");
}
private static void menueCatch()
{
Scanner userIn= new Scanner(System.in);
int userChoice=userIn.nextInt();
String input="";
switch(userChoice)
{
case 1:
{
temp1=getTemp();
scale1=scaleOne();
scale2=toScale();
conv=convert();
displayConversion();
break;
}
case 2:
{
break;
}
}
}
private static double getTemp()
{
double temp;
double currentTemp;
Scanner userIn= new Scanner(System.in);
System.out.print("Enter a temperature to convert as a digit(ex: 100, 32, 10, 0): ");
while(!userIn.hasNextDouble())
{
System.out.println("That is not a valid temperature!");
System.out.print("Re-enter a temperature: ");
userIn.next();
}
temp=userIn.nextDouble();
return temp;
}
private static String scaleOne()
{
Scanner userIn= new Scanner(System.in);
System.out.print("What scale is your temp currently in?"+
"\n1: Fahrenheit" +
"\n2: Celsius" +
"\n3: Kelvin" +
"\nPlease enter 1, 2, or 3: ");
int userChoice = userIn.nextInt();
String scale="";
switch(userChoice)
{
case 1:
{scale= "Fahrenheit";
break;}
case 2:
{scale="Celsius";
break;}
case 3:
{scale="Kelvin";
break;}
default:
{scale= "There was an error in your choice!";}
}
return scale;
}
private static String toScale()
{
Scanner userIn= new Scanner(System.in);
System.out.print("What scale would you like to convert to?"+
"\n1: Fahrenheit" +
"\n2: Celsius" +
"\n3: Kelvin" +
"\nPlease enter 1, 2, or 3: ");
int userChoice = userIn.nextInt();
String scale2="";
switch(userChoice)
{
case 1:
{scale2= "Fahrenheit";
break;}
case 2:
{scale2="Celsius";
break;}
case 3:
{scale2="Kelvin";
break;}
default:
{scale2= "There was an error in your choice!";}
}
return scale2;
}
public static double convert()
{
double converts;
if (scale1.equals("Fahrenheit") && scale2.equals("Kelvin")) {
converts = (temp1 + 459.67) * (5.0 / 9.0);
}
else if (scale1.equals("Fahrenheit") && scale2.equals("Celsius")) {
converts = (temp1 - 32) * (5.0 / 9.0);
}
else if (scale1.equals("Celsius") && scale2.equals("Kelvin")) {
converts = temp1 + 273.15;
}
else if (scale1.equals("Celsius") && scale2.equals("Fahrenheit")) {
converts = temp1 * (9.0 / 5.0) + 32;
}
else if (scale1.equals("Kelvin") && scale2.equals("Fahrenheit")) {
converts = temp1 * (9.0 / 5.0) - 459.67;
}
else { // Kelvin to Celsius
converts = temp1 - 276.15;
}
return converts;
}
private static void displayConversion()
{
System.out.print("Your final temp is: " +conv+' '+scale2+' ');
}
private static char contOption()
{
char answer;
Scanner userIn=new Scanner(System.in);
System.out.print("\nDo you wish to convert another temp?(Y/N): ");
answer=userIn.next().toUpperCase().charAt(0);
return answer;
}
}