Question

我的gulp应用似乎工作正常，但jQuery因某些原因没有被执行。我是Gulp的新手，我无法弄清楚这个问题。

这是我的gulpfile.js

var gulp = require('gulp');
var sass = require('gulp-sass');
var jshint = require('gulp-jshint');
var stylish = require('jshint-stylish');
var concat = require('gulp-concat');
var uglify = require('gulp-uglify');
var rename = require("gulp-rename");
var imagemin = require('gulp-imagemin');
var plumber = require('gulp-plumber');
var fixmyjs = require("gulp-fixmyjs");
var browserSync = require('browser-sync').create();
var reload = browserSync.reload;

// sass
gulp.task('sass', function () {
    gulp.src('./sass/**/*.scss')
        .pipe(sass())
        .pipe(gulp.dest('./'));
});

// js
gulp.task('js', function () {
    gulp.src(['./js/src/*.js'])
        .pipe(jshint())
        .pipe(jshint.reporter(stylish))
        .pipe(jshint.reporter('fail'))
        .pipe(concat('scripts.js'))
        .pipe(rename({suffix: '.min'}))
        .pipe(fixmyjs({
            "asi": true
        }))
        .pipe(uglify().on('error', function(e){
            console.log(e);
         }))
        .pipe(gulp.dest('js'));
});

gulp.task('images', function() {
    gulp.src('./src/images/*')
        .pipe(imagemin({
            optimizationLevel: 7,
            progressive: true
        }))
    .pipe(gulp.dest('dist/images'))
});

// browser sync and watch
gulp.task('watch', function() {
    browserSync.init({
        files: ['./**/*.php'],
        proxy: 'http://neontetra.local/',
    });
    gulp.watch('./sass/**/*.scss', ['sass', reload]);
    gulp.watch('./js/src/*.js', ['js', reload]);
    gulp.watch('./src/images/*', ['images', reload]);
});

gulp.task('default', ['sass', 'images', 'js', 'watch']);

这是package.json

{
  "name": "neontetra",
  "version": "1.0.0",
  "description": "[![Build Status](https://travis-ci.org/Automattic/_s.svg?branch=master)](https://travis-ci.org/Automattic/_s)",
  "main": "index.js",
  "scripts": {
    "test": "echo \"Error: no test specified\" && exit 1"
  },
  "author": "",
  "license": "ISC",
  "dependencies": {
    "browser-sync": "^2.17.3",
    "gulp-concat": "^2.6.0",
    "gulp": "^3.9.1",
    "gulp-fixmyjs": "^1.0.2",
    "gulp-imagemin": "^3.0.3",
    "gulp-jshint": "^2.0.1",
    "gulp-plumber": "^1.1.0",
    "gulp-sass": "^2.3.2",
    "gulp-rename": "^1.2.2",
    "gulp-uglify": "^2.0.0",
    "jquery": "^3.1.1",
    "jshint": "^2.9.3",
    "jshint-stylish": "^2.2.1"
  },
  "devDependencies": {

  }
}

这是main.js

(function($){
    "use strict";
    console.log('here');
    $('header').hide();
})(jQuery);

控制台面板抛出错误Uncaught ReferenceError: jQuery is not defined

如何让jQuery与Gulp合作？

Answer 1

您确定先在其他所有内容之前下载jQuery库吗？

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>

Answer 2

存在多个问题。

首先，在index.html中，我删除了

部分

<!-- build:js scripts/main.min.js -->
<!-- endbuild -->

gulp用于合并JS并将其缩小为1个文件。修复是添加以下

<!-- build:js scripts/main.min.js -->
  <script src="scripts/vendors/jquery-1.9.1.min.js"></script>
  <script src="scripts/vendors/waypoints.min.js"></script>
  <script src="scripts/main.js"></script>
  <!-- endbuild -->

其次，在gulp scripts任务中，我必须告诉gulp要复制的所有脚本。该修复看起来像

gulp.task('scripts', () =>
  gulp.src([
    // Note: Since we are not using useref in the scripts build pipeline,
    //       you need to explicitly list your scripts here in the right order
    //       to be correctly concatenated
    './app/scripts/vendors/jquery-1.9.1.min.js',
    './app/scripts/vendors/waypoints.min.js',
    './app/scripts/main.js'
    // Other scripts
  ])

最后，如@Wolfgang Leon所述，jQuery v3.2.0在某种程度上不兼容，因此我将其替换为jQuery v1.9.1

这有助于我完全解决问题。 #learnednewthings

Gulp - jQuery没有定义

2 个答案: