Question

这可能看起来很明显，但我无法解释No match available error。下面，您可以找到我正在使用的简单匹配函数的定义。

函数内部的相同指令运行没有问题，但是调用函数会引发错误。你能帮我找出错误吗？

import scala.util.matching.Regex

def regexParsing(inputRecord:String, inputRegex:String, listOfFields:Seq[String], fieldsToRemove:Seq[String]): scala.collection.Map[String,Any] = {
    val logPattern = new Regex(inputRegex, listOfFields:_*)
    val result = logPattern.findAllIn(inputRecord)
    val resultMap = result.groupNames.map(a => Map(a.toString -> result.group(a))).reduce(_++_)
    return resultMap
}

val inputRecord = """s2222f"""
val inputRegex = """(.*)"""
val listOfFields = Seq("field")
val fieldsToRemove = Seq("field1", "field2")

// working 
val logPattern = new Regex(inputRegex, listOfFields:_*)
val result = logPattern.findAllIn(inputRecord)
val resultMap = result.groupNames.map(a => Map(a.toString -> result.group(a))).reduce(_++_)

// not working 
regexParsing(inputRecord, inputRegex, listOfFields, fieldsToRemove)

Answer 1

试试2.12？关于推进迭代器的限制是最终解决的API中的问题。

$ scala
Welcome to Scala 2.12.0-RC1 (Java HotSpot(TM) 64-Bit Server VM, Java 1.8.0_101).
Type in expressions for evaluation. Or try :help.

scala> :pa
// Entering paste mode (ctrl-D to finish)

import scala.util.matching.Regex

def regexParsing(inputRecord:String, inputRegex:String, listOfFields:Seq[String], fieldsToRemove:Seq[String]): scala.collection.Map[String,Any] = {
    val logPattern = new Regex(inputRegex, listOfFields:_*)
    val result = logPattern.findAllIn(inputRecord)
    val resultMap = result.groupNames.map(a => Map(a.toString -> result.group(a))).reduce(_++_)
    return resultMap
}

val inputRecord = """s2222f"""
val inputRegex = """(.*)"""
val listOfFields = Seq("field")
val fieldsToRemove = Seq("field1", "field2")

// working 
val logPattern = new Regex(inputRegex, listOfFields:_*)
val result = logPattern.findAllIn(inputRecord)
val resultMap = result.groupNames.map(a => Map(a.toString -> result.group(a))).reduce(_++_)

// Exiting paste mode, now interpreting.

import scala.util.matching.Regex
regexParsing: (inputRecord: String, inputRegex: String, listOfFields: Seq[String], fieldsToRemove: Seq[String])scala.collection.Map[String,Any]
inputRecord: String = s2222f
inputRegex: String = (.*)
listOfFields: Seq[String] = List(field)
fieldsToRemove: Seq[String] = List(field1, field2)
logPattern: scala.util.matching.Regex = (.*)
result: scala.util.matching.Regex.MatchIterator = non-empty iterator
resultMap: scala.collection.immutable.Map[String,String] = Map(field -> s2222f)

scala> regexParsing(inputRecord, inputRegex, listOfFields, fieldsToRemove)
res0: scala.collection.Map[String,Any] = Map(field -> s2222f)

scala> :quit

如何正确使用scala.util.matching.Regex？

1 个答案: