Question

我正在使用登录系统，该系统根据usertype和user_activation_status重定向到适当的URL。以下代码：

$.post(
        './assets/tasks/process-login.php',
        {
            email:email,
            password:password
        },
        function(data){
            console.log(data);
            if(data==1){
                $("#lblMessage_frmLogin").css("color","green");
                $("#lblMessage_frmLogin").text("Login successful.. Redirecting to your homepage").fadeIn();
                window.location.href=siteurl + '/my-home/';
            }else if(data==-2){
                $("#lblMessage_frmLogin").css("color","red");
                $("#lblMessage_frmLogin").html("Looks like you haven't registered with us, Please <a href='" + siteurl + "/home'> click here </a> to register.").fadeIn();
            }else{
                $("#lblMessage_frmLogin").css("color","red");
                $("#lblMessage_frmLogin").text("Login unsuccessful, please recheck the details you have entered.").fadeIn();
            }
        });

由于担心会延长帖子，我没有加入./assets/tasks/process-login.php。它只是回显1表示成功，0表示错误密码，-2表示未存在的电子邮件。

重定向到/ my-home /后，会在页面标题中检查user_activation_status，而后者又必须将页面重定向到适当的页面。

/my-home/index.php

<?php include './includes/meta.php';
      include './includes/header-nav.php';
      check_user_action_status($_SESSION['logged_in_userid']);
    switch ($usertype) {
    case 1:
        $selected_dashboard='candidate-dashboard.php';
        break;
    case 2:
        $selected_dashboard='expert-dashboard.php';
        break;
    case 3:
        $selected_dashboard='admin-dashboard.php';
        break;

    default:
        if($usertype=="") user_logout();
        break;

}
    include './includes/page-content/'.$selected_dashboard; 
    include './includes/footer.php'; 
?>

功能：

/**
Function to check if the user has confirmed email and filled profile, uploaded docs or disabled.
Params : userid
Returns none; Redirects to appropriate page, or logs out if user not logged in.
**/
function check_user_action_status($userid){
    $userid=trim(sqlescapes($userid));
    if($get_row = mysqli_query($GLOBALS['conn'], "select user_type,user_activation_status from tbl_users where user_id=$userid")){
        if (mysqli_num_rows($get_row) > 0) {
            if($got_row=mysqli_fetch_object($get_row)){
                if($got_row->user_activation_status==0){
                    header("location:".$GLOBALS['siteurl']."/my-home/confirm-email");
                }else if($got_row->user_activation_status==1){
                    header("location:".$GLOBALS['siteurl']."/my-home/my-profile?id=start");
                }else if($got_row->user_activation_status==-1){
                    header("location:".$GLOBALS['siteurl']."/my-home/disabled-account");
                }

                if($got_row->user_type==2){
                    if($got_row->user_activation_status==2){
                        header("location:".$GLOBALS['siteurl']."/my-home/upload-docs");
                    }
                }
            }
        }else{
            user_logout();
        }
        }else{
            user_logout();
        }

}

（请注意，$GLOBALS['siteurl']='http://localhost/tlaqi/'。user_logout()和sqlescapes()是相应功能的用户定义函数。

逻辑在localhost上完美运行但是当我上传到服务器后，在登录后，即使符合条件，它也不会重定向到check_user_action_status()中定义的适当页面。相反，它只是加载/my-home/index.php。

我哪里错了？

Answer 1

在输出发送之前必须设置标题。在php脚本的最开头添加ob_start();。如果它包含另一个文件，那么不要使用？＆gt;最后。

或尝试

header("location:".$GLOBALS['siteurl']."/my-home/confirm-email");
exit();

或echo "<script>location='your_url.com'</script>";

Answer 2

之前我遇到过这样的问题，现在我不再使用header('Location: pageExample.php');，而是使用JavaScript document.location。

改变你的：

header('Location: page1.php');

对于这样的事情：

echo "<script type='text/javascript'> document.location = 'page1.php'; </script>";

从JS重定向后，标头位置在服务器上不起作用（但在localhost上工作）

2 个答案: