我正在努力保存数据,用户也可以输入具有特殊字符的数据。我在保存数据时编码了名称字符串,但作为响应,json数组即将到来。我们如何在获得响应时再次解码数据。
使用编码字符串保存数据。
$scope.saveData = function(){
$scope.loading = true;
$scope.Name = encodeURI(this.group.name);
$scope.Name1 = encodeURIComponent($scope.groupName);
$scope.groupData = 'Name='+$scope.Name1+'&Users='+$scope.UserID.join();
DataService.createUsers($scope.groupData).success(function (data) {
}).catch(function (err) {
})
.finally(function () {
});
}
Js获取控制器中用户的数据。
localStorageService.set('users', grps.allUsers);
localStorageService.bind($scope, 'users');
function getMyUsers(){
DataService.getMyUsers().then(function successCallback(response)
{
$scope.users.length = 0;
$scope.users.push({'data': response.data.results});
},function errorCallback(response) {
console.log(response);
});
}
<ul>
<li ng-repeat="user in users[0].data track by $index">
<div class="list_left">
<div class="pro_text">
<h2 class="group_title"><a href="javascript:;">{{ usr.Name }}</a></h2>
<p class=""></p>
<span>Created By: {{ user.createdBy.ownerName }} {{ user.createdBy.lastName }}</span>
</div>
</div>
</li>
</ul>
答案 0 :(得分:0)
使用decodeURIComponent
var response = {};
DataService.createUsers($scope.groupData).success(function (data) {
data.yourArray.forEach(function(key, value){
response[decodeURIComponent(key[0])] = decodeURIComponent(key[1]);
});
console.log("new response", response);
})