Question

我在使用php比较两个数组和打印结果时遇到了问题。我在下面解释我的代码。

$comment = json_encode(array(array('day_id' => '2', 'comment' => 'vodka1'), array('day_id' => '3', 'comment' => 'vodka2')));
$result = json_encode(array(array('day_id' => '1', 'restaurant' => '193'), array('day_id' => '2', 'restaurant' => '193'), array('day_id' => '3', 'restaurant' => '193')));
$arrComment = json_decode($comment, true);
$arrResult = json_decode($result, true);
foreach($arrResult AS $keyResult => $dataResult){
    $day_id = $dataResult['day_id'];
    $restaurant = $dataResult['restaurant'];
    $strComment = '';
    $getKey='';
    $getKey = array_search($day_id, array_column($arrComment, 'day_id'));
    if($getKey ==''){
        $strComment = '';
    }else{
        $strComment = $arrComment[$getKey]['comment'];
    }
     $insertintodetails[]=array("day_id"=>$day_id,"rest"=>$restaurant,"comment"=>$strComment);
}
echo json_encode($insertintodetails);

我在这里得到以下结果。

[{"day_id":"1","rest":"193","comment":""},{"day_id":"2","rest":"193","comment":""},{"day_id":"3","rest":"193","comment":"vodka2"}]

但我的结果应该如下所示。

[{"day_id":"1","rest":"193","comment":""},{"day_id":"2","rest":"193","comment":"vodka1"},{"day_id":"3","rest":"193","comment":"vodka2"}]

此处我的要求是，如果day_id from $result中不存在$comment，则相应的评论字段将保持空白。请帮帮我。

Answer 1

试试这个解决方案它会正常工作。这里array_search()总是返回键或布尔值（http://php.net/manual/en/function.array-search.php）。

所以只需要检查$getKey是否为假或任何密钥。

$comment = json_encode(array(array('day_id' => '2', 'comment' => 'vodka1'), array('day_id' => '3', 'comment' => 'vodka2')));
$result = json_encode(array(array('day_id' => '1', 'restaurant' => '193'), array('day_id' => '2', 'restaurant' => '193'), array('day_id' => '3', 'restaurant' => '193')));
$arrComment = json_decode($comment, true);
$arrResult = json_decode($result, true);

foreach($arrResult as $keyResult => $dataResult){
    $day_id = $dataResult['day_id'];
    $restaurant = $dataResult['restaurant'];
    $strComment = '';
    $getKey='';
    $getKey = array_search($day_id, array_column($arrComment, 'day_id'));

    if(is_numeric($getKey)){
        $strComment = $arrComment[$getKey]['comment'];
    }else{
        $strComment = '';
    }
     $insertintodetails[]=array("day_id"=>$day_id,"rest"=>$restaurant,"comment"=>$strComment);
}
echo json_encode($insertintodetails);

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1 个答案: