如何将此更新查询写入codeigniter？

Question

查询：

    $sql = "UPDATE sports SET status = 0 WHERE sport_id NOT IN (".$sport_id.") and user_id='".$user_id."'";

Answer 1

试试这个，它适合你...

$this->db->where_not_in('sport_id', explode(",",$sport_id));
$this->db->where('user_id', $user_id);
$this->db->update("sports", array("status" => 0));