如何使用VBScript在主字符串中查找重复的子字符串?
例如,如果字符串是
str = "Google mail, Google Maps, Google drive, Google music, Google play, Google office"
我需要在上面的字符串中重复的子字符串。它的数量。
由于
答案 0 :(得分:2)
这将给出给定子字符串中所有单词的计数。
str = "Google mail, Google Maps, Google drive, Google music, Google play, Google office"
Function RemoveDuplicates(str)
If Trim(str) = "" Then
RemoveDuplicates = Array()
Exit Function
End If
Set d = CreateObject("Scripting.Dictionary")
d.CompareMode = vbTextCompare 'make dictionary case-insensitive
For Each elem In Split(str)
d(elem) = True
Next
RemoveDuplicates = d.Keys
End Function
sUniques = RemoveDuplicates(str)
For k = 0 To UBound(sUniques)
iCount = len(str) - len(replace(str, sUniques(k), ""))
msgbox "The string " & sUniques(k) & " appeared " & iCount/len(sUniques(k)) & " times"
Next
中的第一个功能
答案 1 :(得分:1)
通过4个简单步骤查找单词重复:
从字符串中移除interpunction并将连续空格连接到单个空格,例如使用regular expression replacement。
Set re = New RegExp
re.Pattern = " *[.,;!?'""_-] +| +"
re.Global = True
str = re.Replace(str, " ")
Split空格处的字符串。
将每个单词作为键放入Dictionary
。如果单词已经exists。
For Each word In dict.Keys
If IsEmpty(mfu) Then
mfu = word
ElseIf dict(word) > dict(mfu) Then
mfu = word
End If
Next
WScript.Echo mfu & ": " & dict(mfu)
答案 2 :(得分:1)
mask = df.t1 <= df.t2
print (mask)
0 False
dtype: bool
答案 3 :(得分:0)
Sub DeDup
Set Dict = CreateObject("Scripting.Dictionary")
Do Until Inp.AtEndOfStream
On Error Resume Next
Line=Inp.readline
Dict.Add Line, ""
If Err.Number <> 0 then
If LCase(Arg(1)) = "l" then
Dict.Remove Line
Dict.Add Line, ""
End If
End If
Loop
For Each thing in Dict.Keys()
Outp.writeline thing
Next
End Sub
这使用脚本字典来重复删除行。您可以使用Split()
获取一系列单词。将每一个添加到字典中,如果它错误,它就是一个字典。
答案 4 :(得分:0)
查找出现事项:
baseString = "Google mail, Google Maps, Google drive, Google music, Google play, Google office"
subString = "Google"
MsgBox "The "& chr(34) & subString & chr(34) & " appeared " &_
findOccurancesCount(baseString, subString) & " times !" & vbCrLF &_
"in " & vbCrLF & chr(34) & baseString & chr(34)_
,vbInformation,"FindOccurancesCount"
'*********************************************************************************
Function findOccurancesCount(baseString, subString)
occurancesCount = 0
i = 1
Do
foundPosition = InStr(i, Lcase(baseString), Lcase(subString))
If foundPosition > 0 Then
occurancesCount = occurancesCount + 1
i = foundPosition + 1
End If
Loop While foundPosition <> 0
findOccurancesCount = occurancesCount
End Function
'*********************************************************************************