Question

选择所有列数据为上

目前我正在使用upper(columnname) as 'xyz'这是失去名字，我不想要

我的要求是select col1,col2,col3,col4 from xyz table

我正在寻找一种方法，可以在单一语法中将所有4个col设置为更高，而不会丢失列名

例如：select Upper(col1,col2,col3,col4) from xyz table

Answer 1

试试这个

DECLARE @columnName varchar(25)
DECLARE @cursor CURSOR
declare @sql nvarchar(1000)
declare @tableName as nvarchar(30)
set @tableName = 'YOURTABLE'
SET @cursor = CURSOR FOR 
select c.name from sys.columns c inner join sys.tables t on c.object_id = t.object_id 
where c.object_id = (select object_id from sys.tables where name  = @tableName )


OPEN @cursor

FETCH NEXT

FROM @cursor INTO @columnName
WHILE @@FETCH_STATUS = 0
BEGIN


set @sql = 'update YOURTABLE set '+ @columnName +' =   upper(' + @columnName + ') where YOURTABLE.'+@columnName+' = YOURTABLE.'+ @columnName+''
EXEC(@sql)


FETCH NEXT
FROM @cursor INTO @columnName
END

CLOSE @cursor
DEALLOCATE @cursor

更新：您必须更新所有列，以便所有列都变为大写

注意：请在进行之前备份您的餐桌将YOURTABLE更改为您的表名

Answer 2

试试这个：

  select UPPER(col1) AS Col1,UPPER(col2) AS col2,UPPER(col3) as
  col3,UPPER(col4 ) as col4 from xyz table

选择所有列数据为上部

2 个答案: