Question

有没有关于如何在不使用String替换的情况下替换字符串中的单词的解决方案？

你们都可以看到这就像硬编码一样。有没有什么方法可以动态制作它？我听说有一些库文件可以动态制作但我不太确定。

任何专家都能给我一些解决方案吗？非常感谢你，祝你有愉快的一天。

for (int i = 0; i < results.size(); ++i) {
                // To remove the unwanted words in the query
                test = results.toString();
                String testresults = test.replace("numFound=2,start=0,docs=[","");
                testresults = testresults.replace("numFound=1,start=0,docs=[","");
                testresults = testresults.replace("{","");
                testresults = testresults.replace("SolrDocument","");
                testresults = testresults.replace("numFound=4,start=0,docs=[","");
                testresults = testresults.replace("SolrDocument{", "");
                testresults = testresults.replace("content=[", "");
                testresults = testresults.replace("id=", "");
                testresults = testresults.replace("]}]}", "");
                testresults = testresults.replace("]}", "");
                testresults = testresults.replace("}", "");

Answer 1

在这种情况下，您需要学习regular expression和内置字符串函数String.replaceAll()来捕获所有可能不需要的单词。例如：

test.replaceAll("SolrDocument|id=|content=\\[", "");

Answer 2

只需创建并使用自定义的String.replace（）方法，该方法恰好使用其中的String.replace（）方法：

public static String customReplace(String inputString, String replaceWith, String... stringsToReplace) {
    if (inputString.equals("")) { return replaceWith; }
    if (stringsToReplace.length == 0) { return inputString; }

    for (int i = 0; i < stringsToReplace.length; i++) {
        inputString = inputString.replace(stringsToReplace[i], replaceWith);
    }

    return inputString;
}

在上面的示例方法中，您可以在 stringsToReplace 参数中提供任意数量的字符串，只要它们用逗号（，）分隔即可。它们将全部替换为您为 replaceWith 参数提供的内容。

以下是如何使用它的示例：

String test = "This is a string which contains numFound=2,start=0,docs=[ crap and it may also "
            + "have numFound=1,start=0,docs=[ junk in it along with open curly bracket { and "
            + "the SolrDocument word which might also have ]}]} other crap in there too.";

testResult = customReplace(strg, "", "numFound=2,start=0,docs=[ ", "numFound=1,start=0,docs=[ ", 
                         + "{ ", "SolrDocument ", "]}]} ");

System.out.println(testResult);

您还可以传递单个字符串数组，其中包含元素中所有不需要的字符串，并将该数组传递给 stringsToReplace 参数，例如：

String test = "This is a string which contains numFound=2,start=0,docs=[ crap and it may also "
            + "have numFound=1,start=0,docs=[ junk in it along with open curly bracket { and "
            + "the SolrDocument word which might also have ]}]} other crap in there too.";

String[] unwantedStrings = {"numFound=2,start=0,docs=[ ", "numFound=1,start=0,docs=[ ", 
                            "{ ", "SolrDocument ", "]}]} "};

String testResult = customReplace(test, "", unwantedStrings);

System.out.println(testResult);

替换String中的单词而不使用String replace

2 个答案: