从C中的函数返回一个字符串数组

Question

我试图创建一个以char **作为参数并返回char **类型的函数。此函数的目的是按字母顺序对字符串列表进行排序。我有这个代码，我无法弄清楚为什么我的代码不起作用。我看到这个答案“Returning an array of strings in C”，但我仍然无法弄清楚为什么下面的代码会崩溃......

这是我的代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char** a_to_z_ordering (char**, int);

int main(int argc, char **argv) {
    char** unordered;
    //char** ordered;

    unordered = malloc(50*150); //is it ok to use more space? (In case my max is what the numbers declare)
    //ordered = malloc(50*150); //should I declare like this?

    for(int i = 0; i<50; i++) {
        unordered[i] = malloc(150*sizeof(char));
    }

    //for(int i = 0; i<50; i++) {
    //  ordered[i] = malloc(150*sizeof(char));
    //}

    strcpy(unordered[0], "ba");
    strcpy(unordered[1], "ab");
    strcpy(unordered[2], "aa");

    printf("The list of strings without alphabetical ordering:\n\n");
    for (int i = 0; i<3; i++) {
        printf("This is string %d: %s\n", i, unordered[i]);
    }

    //arrange strings to alphabetical ordering
    char** ordered = a_to_z_ordering(unordered, 3); //3 elements + \0?

    printf("\n\nThe list of strings WITH alphabetical ordering:\n\n");
    for (int i = 0; i<3; i++) {
        printf("This is string %d: %s\n", i, ordered[i]);
    }

    return 0;
}

char** a_to_z_ordering (char** arrayOfStrings, int arraySize) {
    char* tempString = malloc(150*sizeof(char));

    arrayOfStrings = malloc(50*150);
    for(int i = 0; i<arraySize; i++) {
        arrayOfStrings[i] = malloc(150*sizeof(char));
    }

    for(size_t i = 1; i < arraySize; i++) {
        for(size_t n = 1; n <arraySize; n++) {
            if(strcmp(arrayOfStrings[n-1], arrayOfStrings[n]) > 0) {
                strcpy(tempString, arrayOfStrings[n-1]);
                strcpy(arrayOfStrings[n-1], arrayOfStrings[n]);
                strcpy(arrayOfStrings[n], tempString);
            }
        }
    }
    return arrayOfStrings;
}