Question

我正在通过来自邀请行的sender_id获取邀请数和每个邀请的行，我正在从用户表中检索用户的详细信息。

我想在同一个邀请数组中添加用户的详细信息。我试着像这样添加。

    function getInvitations()
{
    $database = new Database(ContactsConstants::DBHOST,ContactsConstants::DBUSER,ContactsConstants::DBPASS,ContactsConstants::DBNAME);
    $dbConnection = $database->getDB();

    $stmt = $dbConnection->prepare("SELECT * FROM `Invitation` WHERE Invitation.invitee_no = ?");
    $stmt->execute(array($this-> invitee_no));
    $rows = $stmt->fetchAll(PDO::FETCH_ASSOC);

    $invitations = array();

    if (count($rows) > 0) {

        foreach($rows as $row)
        {
            $stmt = $dbConnection->prepare("Select * from Users where user_id =?");
            $stmt->execute(array($row['sender_id']));

            $result = $stmt->fetch(PDO::FETCH_ASSOC);

            $invitations[] = $row;
            $invitations[] = $result;
        }

        $response = array("status" => 1, "message" => "Success", "Invitations" => $invitations);
        return json_encode($response);
    }

    else {
        $response = array("status"=>-1,"message"=>"Invitations list is empty");
        return json_encode($response);
    }
}

输出我是这样的：

    {
  "status": 1,
  "message": "Success",
  "Invitations": [
    {
      "invitation_id": "369",
      "date": "12/08/2016",
      "invitee_no": "8655864341",
      "status": "1",
      "sender_id": "44"
    },
    {
      "user_id": "44",
      "user_name": "Angel",
      "password": "angel",
      "profile_image": "a8625093a2e95ee6b5042456b7cccc20.png",
      "device_id": "eVOnz8AMVOs:APA91bHuq9Q4FLcOewUCSAQu79aZNeQsb4710k66g1MHDfZUZWa4ZcARs0SekUfnYUt5sTiKeXfFk_Gg_LdtSKk-pTAaQLxPe9UMkYG9-d-IkDRlGYxkzonQ1h2YN78S7RU0x90NAby_",
      "mobile_no": "9090966666",
      "email_id": "kjfhg@half.com",
      "full_name": "ajjdjd",
      "job_title": "sxsaca",
      "home_address": "scacac",
      "work_phone": "ugiuygitf",
      "work_address": "bbuyiytfi"
    },
  ]}

但我希望在一个数组中同时包含两个细节。我怎么能得到这个？有人能帮忙吗？谢谢..

Answer 1

问题是你正在推动$invitations变量两个不同的关联数组。这里的解决方案是将两个数组（array_merge）的元素合并为一个，然后将其推送到$invitation。

尝试更改此代码：

$invitations[] = $row;
$invitations[] = $result;

由此：

$invitations[] = array_merge($row, $result);

编辑：

要解决警告array_merge(): Argument #2 is not an array，请尝试使用转换强制$result数组类型：

$invitations[] = array_merge($row, (array)$result);

Answer 2

使用以下功能，因为@nanocv告诉你必须改变如下

<?php
   function getInvitations()
{
    $database = new Database(ContactsConstants::DBHOST,ContactsConstants::DBUSER,ContactsConstants::DBPASS,ContactsConstants::DBNAME);
    $dbConnection = $database->getDB();

    $stmt = $dbConnection->prepare("SELECT * FROM `Invitation` WHERE Invitation.invitee_no = ?");
    $stmt->execute(array($this-> invitee_no));
    $rows = $stmt->fetchAll(PDO::FETCH_ASSOC);

    $invitations = array();

    if (count($rows) > 0) {

        foreach($rows as $row)
        {
            $stmt = $dbConnection->prepare("Select * from Users where user_id =?");
            $stmt->execute(array($row['sender_id']));

            $result = $stmt->fetch(PDO::FETCH_ASSOC);
            $final_array = array_merge($row,$result);
            $invitations[] = $final_array;
        }

        $response = array("status" => 1, "message" => "Success", "Invitations" => $invitations);
        return json_encode($response);
    }

    else {
        $response = array("status"=>-1,"message"=>"Invitations list is empty");
        return json_encode($response);
    }
}

?>

希望这会有所帮助！

如何在一个数组中添加另一行？

2 个答案: