我正在尝试使用Ninject加载依赖项。但是NinjectWebCommon无法在引用的程序集中加载NinjectModules。
$(document).ready(function(){
var yourCharacter;
var enemy1;
var enemy2;
var enemy3;
$('#c1').text("Darth Vader");
$('#c2').text("Luke Skywalker");
$('#c3').text("Obi Won");
$('#c4').text("Darth Maul");
var health = $('#c1hp').data('hp');
$('#c1hp').html(health);
var health = $('#c2hp').data('hp');
$('#c2hp').html(health);
var health = $('#c3hp').data('hp');
$('#c3hp').html(health);
var health = $('#c4hp').data('hp');
$('#c4hp').html(health);
$('.charContainer').on('click', function(){
yourCharacter = $(this);
$('#your').append(yourCharacter);
enemy1 = $('.vader');
$('#enemies').append(enemy1);
})
});
下面是我试图加载的模块
using System;
using System.Web;
using Microsoft.Web.Infrastructure.DynamicModuleHelper;
using Ninject;
using Ninject.Web.Common;
public static class NinjectWebCommon
{
private static readonly Bootstrapper bootstrapper = new Bootstrapper();
/// <summary>
/// Starts the application
/// </summary>
public static void Start()
{
DynamicModuleUtility.RegisterModule(typeof(OnePerRequestHttpModule));
DynamicModuleUtility.RegisterModule(typeof(NinjectHttpModule));
bootstrapper.Initialize(CreateKernel);
}
/// <summary>
/// Stops the application.
/// </summary>
public static void Stop()
{
bootstrapper.ShutDown();
}
/// <summary>
/// Creates the kernel that will manage your application.
/// </summary>
/// <returns>The created kernel.</returns>
private static IKernel CreateKernel()
{
var kernel = new StandardKernel();
try
{
kernel.Bind<Func<IKernel>>().ToMethod(ctx => () => new Bootstrapper().Kernel);
kernel.Bind<IHttpModule>().To<HttpApplicationInitializationHttpModule>();
RegisterServices(kernel);
return kernel;
}
catch
{
kernel.Dispose();
throw;
}
}
/// <summary>
/// Load your modules or register your services here!
/// </summary>
/// <param name="kernel">The kernel.</param>
private static void RegisterServices(IKernel kernel)
{
}
}
我无法弄清楚为什么它无法加载模块?
答案 0 :(得分:2)
经过一些头部敲打会议,我发现我需要打电话
kernel.Load<SecurityModule>();
在NinjectWebCommon的RegisterServices方法中。