我一直在努力进行GUI标签更新,这是一款简单的游戏,需要我完成其GUI,显示玩家得分和掉期数量的标签不会更改。如果有人能回答我的问题,我会感激不尽。
class StatusBar(tk.Frame):
def __init__(self,master):
super().__init__(master)
self._simple_player=SimplePlayer()
self._swaps_label=tk.Label(self,
text=self._simple_player.get_swaps())
self._score_label=tk.Label(self,
text=self._simple_player.get_score())
self._swaps_label.pack(side=tk.RIGHT)
self._score_label.pack(side=tk.RIGHT)
class App(object):
def __init__(self, master):
"""
Constructor(SimpleTileApp, tk.Frame)
"""
self._master = master
self._simple_player=SimplePlayer()
self._game = SimpleGame()
self._status=StatusBar(master)
self._status.pack()
self._grid_view = TileGridView(
master, self._game.get_grid(),
width=GRID_WIDTH, height=GRID_HEIGHT, bg='red')
self._grid_view.pack(side=tk.TOP)
我已尝试过Google上的所有方法,但没有任何帮助
我在类中重写一个函数来创建一个新标签,但它似乎没用了
class StatusBar(tk.Frame):
def __init__(self,master):
super().__init__(master)
self._simple_player=SimplePlayer()
self._swaps_label=tk.Label(self,
text=self._simple_player.get_swaps())
self._score_label=tk.Label(self,
text=self._simple_player.get_score())
self._swaps_label.pack(side=tk.RIGHT)
self._score_label.pack(side=tk.RIGHT)
def update_label(self):
if self._simple_player.get_swaps()==-1:
pass
else:
self._swaps_label=tk.Label(self,
text=self._simple_player.get_swaps())
self._score_label=tk.Label(self,
text=self._simple_player.get_score())
self._swaps_label.pack(side=tk.RIGHT)
self._score_label.pack(side=tk.RIGHT)