如何绕过或忽略一个数字？

Question

嘿伙计们这里有蟒蛇noobie。我试图确定用户使用哪种类型的信用卡以及信用卡是否有效。对于以下示例，Visa卡以4号开头，两张卡都有效，因为它们都以4开头。如果前面有零，则跳过它们。是否有内置函数来绕过一个数字或者我必须输入每种情况？感谢您的时间。

示例：

#VISA 0004222222222222 valid
#VISA 4111111111111111 valid

Luhns算法

def计算（creditNumber）：     length = len（creditNumber）     oddSum = 0     evenSum = 0

if ( length == 0 ):
    return 0

else:
    if length % 2 == 0:
        last_number = int( creditNumber[-1])
        evenSum = evenSum + last_number

        return evenSum + calculation( creditNumber[:-1] )

    else:
        last_number = int( creditNumber[-1] )
        last_number = 2 * last_number
        addSum = last_number // 10 + last_number % 10
        oddSum = oddSum + addSum

        return oddSum + calculation( creditNumber[:-1] )

def luhnsCheck():
    creditNumber = input ( "What is your credit card number?" )

    #Check to see which type of credit card the user has

    # American Express starts with 34 or 37 
    if creditNumber[0-15] 


    # Discover starts with 6011

    # MasterCard starts with 51 or 52 or 53 or 54 or 55

    # VISA starts with 4

    creditcard_number = calculation( creditNumber )

    # Valid Card
    if creditcard_number % 10 == 0:
        print( "Valid card" )


    # Invalid Card
    else:
        print( "We do not accept that kind of card" )

luhnsCheck（）

Answer 1

您可以复制当时的号码并将该号码放入列表中。然后，如果第一个数字为零，则将其从列表中删除。重复此操作直到前面没有零。