Swift：在Switch语句中使用比较运算符

Question

我试图创建一个Switch语句（Swift），当case大于给定数字时返回一个String。我知道这可以用＆＃34; if＆＃34;或者＆＃34;否则如果＆＃34;声明，但我想用Switch语句来完成这个。可以这样做，还是Switch语句无法使用＆＃34;大于＆＃34;比较运算符？

var score = 101
var letterGrade = ""

switch score{
    case >100:
    letterGrade = "A+ With Extra Credit"
case 90...100:
    letterGrade = "A"
case 80...89:
    letterGrade = "B"
case 70...79:
    letterGrade = "C"
case 60...69:
    letterGrade = "D"
default:
    letterGrade = "Incomplete"
}

Answer 1

是一个简单的解决方案，将它绑定到这样的常量：

    var score = 101
var letterGrade = ""

switch score{
case let x where x > 100:
    letterGrade = "A+ With Extra Credit"
case 90...100:
    letterGrade = "A"
case 80...89:
    letterGrade = "B"
case 70...79:
    letterGrade = "C"
case 60...69:
    letterGrade = "D"
default:
    letterGrade = "Incomplete"
}

完全符合您的要求