Question

我很难创建一个void / reference函数来确定最高和最低的数字。这些数字先前输入并分配给四个单独的变量。数字的范围只有0到100.我不能使用数组，它必须是一个函数。我的老师说他能够完成6个条件，我接近12个。

void GetGradesFromUser(double& grade1, double& grade2, double& grade3, double& grade4)
{
    cout << "Enter four test grades: ";
    cin >> grade1 >> grade2 >> grade3 >> grade4;
}

double DetermineMaxAndMin(double& grade1, double& grade2, double& grade3, double& grade4)
{
    double max;
    double min;

    if (grade1 >= grade2 && grade1 >= grade3 && grade1 >= grade4)
    {
        max = grade1;
    }

    else if (grade2 >= grade1 && grade2 >= grade3 && grade2 >= grade4)
    {
        max = grade2;
    }

    else if (grade3 >= grade1 && grade3 >= grade2 && grade3 >= grade4)
    {
        max = grade3;
    }

    else max = grade4;

    if (grade1 <= grade2 && grade1 <= grade3 && grade1 <= grade4)
    {
        min = grade1;
    }

    else if (grade2 <= grade1 && grade2 <= grade3 && grade2 <= grade4)
    {
        min = grade2;
    }

    else if (grade3 <= grade1 && grade3 <= grade2 && grade3 <= grade4)
    {
        min = grade3;
    }

    else min = grade4;
}

Answer 1

如果您不能使用数组和循环，并希望在不超过6个条件的情况下获得结果，请考虑以下事项：

double DetermineMaxAndMin(double& grade1, double& grade2, double& grade3, double& grade4)
{
    double max = grade1;
    double min = grade1;

    //find max
    if (max < grade2) max = grade2;
    if (max < grade3) max = grade3;
    if (max < grade4) max = grade4;

    //find min
    if (min > grade2) min = grade2;
    if (min > grade3) min = grade3;
    if (min > grade4) min = grade4;
}

诀窍是假设你已经找到了最大/最小值，并在与新值进行比较时替换它的值。

Answer 2

int a [101]; int min = 0; int max = 0;

min = a [0]; MAX = A [0];

for（int i = 0; i＆lt; 101; i ++）{if（min＆gt; a [i]）{min = a [i];}; if（max＆lt; a [i]）{max = a [i];}; };

所以如果你的号码是1 2 3 4;

min = 1; max = 1;最小值为1 1 1 1;每次迭代; 最大值为1 2 3 4;每次迭代;

这是数组daaa的示例。但如果你足够聪明，你可以运用我的方法。你只需要调整我的代码并删除数组部分。

P.S。该代码包含2个条件并对任意数量的数字进行排序。它非常基本，你可以肯定地做到这一点。

确定最高和最低数字

2 个答案: