分析考试结果限制（Java）

Question

我是初学者，我正在从Deitel进行练习如何编程我制作分析考试结果的程序，并输出奖金是否给教师。我的程序工作正常，但我想如果用户输入1或2以外的值，那么它应该给出错误并终止程序。

Following is the code:

    package test;
    import java.util.Scanner;
    public class apple {
        public static void main(String[] args) {
       Scanner input = new Scanner (System.in);
      int failure = 0;
      int passes = 0;
      int counter = 1;
      while (counter <= 10){
          System.out.print("Enter Result (For Pass Enter 1 or for Fail Enter 2): ");
          int result = input.nextInt();
          if (result == 1)
              passes = passes + 1;
          else 
              failure = failure + 1;
          counter = counter + 1;

      }
      System.out.printf("Total Pass Students are %d and Failed are %d" ,passes , failure );`enter code here`
      if (passes > 8)
          System.out.println("\nBonus to instructor");
        }
            }

Answer 1

如何为其他号码抛出异常？您应该使用自己的非常规异常，因此请使用适当的类扩展异常替换它。

      if (result == 1)
          passes = passes + 1;
      else if (result == 2)
          failure = failure + 1;
      else
          throw new Exception("Wrong value");