Question

我的index.php文件（www root）中有以下jQuery：

＆＃13;

$(document).ready(function() {
        $('#loginForm').submit(function() {
            var username = $("#username").val();
            var password = $("#password").val();
            $.post("php/login.php",
                {
                    username: username,
                    password: password
                },
                
            function(data,status){
                $("#loginstatus").html(data);
                alert(data);
        }
                   
        );
            
        });
    });

＆＃13;

和php文件夹中的以下php脚本：

＆＃13;

<?php
    $username = isset($_POST["username"]) ? $_POST["username"] : '' ;
    $password = isset($_POST["password"]) ? $_POST["password"] : '' ;
    $dbhost = "localhost";
    $dbuser = "s150314";
    $dbpass = "password";
    $dbname = "users";
    $loginerror = "";
    
    $conn = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);
    
    $sqlu = "SELECT username FROM users WHERE username LIKE '$username' ";
    $sqlp = "SELECT password FROM users WHERE password LIKE '$password' ";
    $sqlfn = "SELECT FirstName,LastName FROM users WHERE username LIKE '$username' ";
    
    $resultu = mysqli_query($conn, $sqlu) ;
    $resultp = mysqli_query($conn, $sqlp) ;
    $resultfn = mysqli_query($conn, $sqlfn) ;
    
    if (mysqli_num_rows($resultu) > 0 && mysqli_num_rows($resultu) > 0 ) {
        while($row = mysqli_fetch_assoc($resultfn)) {
            $_SESSION["FirstName"] = $row["FirstName"];
        }
        echo "Success!";
        header("Location: ../pages/redirect.php");
    } else {
        echo "Error!";
    }
    
?>

＆＃13;

然而，表格的提交没有变化。理论上我应该被重定向到redirect.php ...如果我将php代码替换回index.php它可以完美地工作。

Answer 1

使用window.location

<script>
$.post("php/login.php",
{
    username: username,
    password: password
},
cache:false,
success:function(data){     
    if(data.status == 'success'){
        window.location.href="http:\\www.site_name.php/pages/redirect.php"";
    }else if(data.status == 'error'){
        alert(data);
    }
}
</script>

<强> PHP

<?
header('Content-type: application/json');
$SqlQuery = "SELECT FirstName,LastName,username FROM users WHERE username LIKE '$username' AND password LIKE '$password'";

$resultu = mysqli_query($conn, $SqlQuery) ;

if (mysqli_num_rows($resultu) > 0 && mysqli_num_rows($resultu) > 0 ) {
    while($row = mysqli_fetch_assoc($SqlQuery)) {
        $_SESSION["FirstName"] = $row["FirstName"];
    }
    $response_array['status'] = 'success';
} else {
    $response_array['status'] = 'error';
}
?>

jQuery POST没有执行php脚本

1 个答案: