我不确定我哪里出错,当我运行代码时,它说错误res.json(res)不是函数......
我的node.js,
exports.inserttopic = function (req, res) {
var topics = new Topics(req.body);console.log(topics)
topics.status = '1';
topics.type = 'topics';
var data = {};
topics.save(function (err, res) {
if (err) {
console.log(err);
return err;
}
data = { status: false, error_code: 1, message: 'Unable to insert' };
if (res) {
data = { status: true, error_code: 0, result: res, message: 'Inserted successfully' };
}
res.json(data);
});
};
答案 0 :(得分:1)
执行topics.save()
而不是res
时,请使用其他变量名称。在您的代码中,您将覆盖原始res
,因此无权访问响应对象。
这就是你的代码看起来像
exports.inserttopic = function (req, res) {
var topics = new Topics(req.body);console.log(topics)
topics.status = '1';
topics.type = 'topics';
var data = {};
topics.save(function (err, mongooseResponse) { \\ Do not use res here
if (err) {
console.log(err);
return err;
}
data = { status: false, error_code: 1, message: 'Unable to insert' };
if (mongooseResponse) {
data = { status: true, error_code: 0, result: mongooseResponse, message: 'Inserted successfully' };
}
res.json(data);
});
};