Question

我是R的初学者。我在R中有数据框如下：

 Id          Values
A_0_d   Low_5524; Low_6412; Hi_50567
A_0_d   Low_5509; Low_6412; Low_6897; Hi_16021
A_0_d   Low_5524; Low_4930; Low_5886
B_1_d   Low_3697; Low_4519; Low_5524
C_3_d   Low_5576; Low_5581
C_3_d   Hi_30246
C_3_d   Low_5576; Hi_30246

我想基于Ids聚合数据帧，即在一行中将相同ID的所有值分组，并保留仅如下的唯一条目：

A_0_d   Low_5524; Low_6412; Hi_50567; Low_5509; Low_6897; Hi_16021; Low_4930; Low_5886  
B_1_d   Low_3697; Low_4519; Low_5524
C_3_d   Low_5576; Low_5581; Hi_30246

我可以使用聚合功能。请指导我。

Answer 1

使用aggregate你可以试试这个

aggregate(Values ~ Id, df, function(x) paste(unique(x), collapse = '; '))

Answer 2

转换＆＃39; data.frame＆＃39;到＆＃39; data.table＆＃39; （setDT(df1)）。然后，split＆＃39;值＆＃39;按"; "分组后，输入“{1}”，unlist输出，获取unique元素和paste

library(data.table)
setDT(df1)[, .(Values = paste(unique(unlist(strsplit(Values, "; "))), 
                                                 collapse="; ")), by = Id]
#   Id
#1: A_0_d
#2: B_1_d
#3: C_3_d
#                                                                           Values
#1: Low_5524; Low_6412; Hi_50567; Low_5509; Low_6897; Hi_16021; Low_4930; Low_5886
#2:                                                   Low_3697; Low_4519; Low_5524
#3:                                                   Low_5576; Low_5581; Hi_30246

Answer 3

使用aggregate即可

aggregate(Values~Id, df, function(x) unique(unlist(strsplit(x, ";"))))

#   Id                                                                         Values
#1  A_0_d Low_5524, Low_6412, Hi_50567, Low_5509, Low_6897, Hi_16021, Low_4930, Low_5886
#2 B_1_d                                                   Low_3697, Low_4519, Low_5524
#3 C_3_d                                                   Low_5576, Low_5581, Hi_30246

聚合具有相同ID的行并仅保留R中的唯一条目

3 个答案: