我正在尝试从史密斯先生那里返回值M,但每当我在下面运行我的代码时,它返回''
// :id will match anything after the / in the url, and set it as the req.params.id value
app.get('/:id', function (req, res) {
console.log("hi you're about to match url id to database id");
//get a prostgres client from the connection pool
pg.connect(connectionString, (err, client, done) => {
//handle connection errors
if (err) {
done();
console.log(err);
return res.status(500).json({ success: false, data: err });
}
//match id in database to id from query in url
const query = client.query("SELECT * FROM items WHERE id =" + req.params.id);
console.log("successfully matched database id value to id value in url");
console.log(req.query);
res.redirect(req.query);
});
});
答案 0 :(得分:2)
python 3
name = input("Please input your name: ")
c=name.strip()[0]
if c.isalpha():
print(c)
python 2:
>>> name = raw_input("Please input your name: ")
Please input your name: Hisham
>>> c=name.strip()[0]
>>> if c.isalpha():
print c
输出py3:
Python 3.5.2 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
Please input your name: dsfgsdf
d
输出py2:
H
答案 1 :(得分:0)
我在这个提议的代码中看到了很多问题。
首先,input()
将输入字符串计算为python表达式,而这不是您想要的,您需要使用raw_input()
。
其次,如果输入包含','isalpha()
将不会返回True。或空格,因此您需要找到另一个指标,例如,如果只允许使用字母字符,您可以这样使用isalpha()
:
name_nospaces = "".join(name.split())
if name_nospaces.isalpha():
...
然后,做name == name.find(' ')
没有多大意义,只需要:
if name.find(' '):
...
答案 2 :(得分:0)
假设您必须找到名字的第一个字符....
def find_initial(name):
i = 0
initial_name_size = len(name)
while True:
name = name[i:]
if name.isalpha():
get_initial = name[0]
return get_initial
else:
i = i+1
if i >= initial_name_size:
return 'There is no initial'
name = input("Please input your name: ")
print find_initial(name)