Question

我正在努力将Cloudinary与我的React Native应用程序集成，并且当我使用Cloudinary API上传时遇到了问题。我正在使用React Native Image Picker从相机胶卷中选择一张图像并使用它来获取源uri - 示例如下。

我从Cloudinary收到错误回复，我不确定它是指什么。 "Invalid file parameter. Make sure your file parameter does not include '[]'"

当我使用调试器时，我可以控制台注销我在请求正文中发送的所有参数。任何建议将不胜感激！

source.uri: /Users/IRL/Library/Developer/CoreSimulator/Devices/817C678B-7028-4C1C-95FF-E6445FDB2474/data/Containers/Data/Application/BF57AD7E-CA2A-460F-8BBD-2DA6846F5136/Documents/A2F21A21-D08C-4D60-B005-67E65A966E62.jpg

async postToCloudinary(source) {
let timestamp = (Date.now() / 1000 | 0).toString();
let api_key = ENV.cloudinary.api;
let api_secret = ENV.cloudinary.api_secret
let cloud = ENV.cloudinary.cloud_name;
let hash_string = 'timestamp=' + timestamp + api_secret
let signature = CryptoJS.SHA1(hash_string).toString();
let upload_url = 'https://api.cloudinary.com/v1_1/' + cloud + '/image/upload'

try {
  let response = await fetch(upload_url, {
    method: 'POST',
    headers: {
      'Accept': 'application/json',
      'Content-Type': 'application/json'
    },
    body: JSON.stringify({
      file: {
        uri: source.uri,
        type: 'image/jpeg'
      },
      api_key: api_key,
      timestamp: timestamp,
      signature: signature
    })
  });

  let res = await response.json();
  console.log(res);
} catch(error) {
  console.log("Error: ", error);
}

}

更新所以我现在有base64编码工作，我想，但我仍然得到同样的错误。

var wordArray = CryptoJS.enc.Utf8.parse(source.uri);
var file = CryptoJS.enc.Base64.stringify(wordArray);

try {
  let response = await fetch(upload_url, {
    method: 'POST',
    headers: {
      'Accept': 'application/json',
      'Content-Type': 'application/json'
    },
    body: JSON.stringify({
      file: {
        uri: file,
        type: 'image/jpeg;base64'
      },
      api_key: api_key,
      timestamp: timestamp,
      signature: signature
    })
  });

Answer 1

事实证明我传入的源数据格式不正确。我能够从我用作已经格式化的数据URI的ImagePicker插件中传入它（ImagePicker示例带有两种捕获源文件的方法，而我使用的是错误的方法）。我能够摆脱CryptoJS的东西，只需传入file: source.uri

上传到Cloudinary API - 文件参数无效

1 个答案: