SchemaTron日期比较

时间:2016-10-14 16:18:02

标签: xslt xpath schematron

<ROOTNODE>
   <Blocks>
     <Block>
    <Ref/>
      <BlockDates Start="2015-10-20" End="2015-10-25" />
      <Types>
        <Type TypeCode="SGL">
         <TypeAllocations>
        <TypeAllocation Start="2015-10-26" End="2015-10-27" />
        <TypeAllocation Start="2015-10-26" End="2015-10-25" />
      </TypeAllocations>
       </Type>
         <Type TypeCode="SGL">
         <TypeAllocations>
        <TypeAllocation Start="2015-10-28" End="2015-10-29" />
        <TypeAllocation Start="2015-10-26" End="2015-10-27" />
      </TypeAllocations>
       </Type>
      </Types>
    </Block>

    <Block>
      <Ref/>
      <BlockDates Start="2015-10-26" End="2015-10-30"/>
       <Types>
        <Type TypeCode="SG">
         <TypeAllocations>
        <TypeAllocation Start="2015-10-31" End="2015-11-01" />
        <TypeAllocation Start="2015-10-25" End="2015-10-24" />
      </TypeAllocations>
       </Type>
         <Type TypeCode="SG">
         <TypeAllocations>
        <TypeAllocation Start="2015-10-21" End="2015-10-25" />
        <TypeAllocation Start="2015-10-23" End="2015-11-27" />
      </TypeAllocations>
       </Type>
      </Types>
    </Block>
   </Blocks>
   </ROOTNODE>

我正试图找出一种方法来判断&lt; TypeAllocation @Start和@ End&gt;日期在&lt; BlockDates @Start和@End&gt;之外日期。可以有任意数量的&lt; TypeAllocation&gt;元素和&lt;类型&gt;元素。在所有情况下,上述情况都应失败。以下是我的尝试。但是我感觉它离开了,因为它只发现了第一个。非常感谢任何帮助!

   <sch:pattern name="Testing Start and End dates">
                                                                                <sch:rule context="blk:InvBlock">
                                                                                    <sch:report test="translate(blk:InvBlockDates/@Start, '-', '') &lt;= translate(blk:RoomTypes/blk:RoomType/blk:RoomTypeAllocations/blk:RoomTypeAllocation/@Start, '-', '') or translate(blk:InvBlockDates/@End, '-', '') &lt;= translate(blk:RoomTypes/blk:RoomType/blk:RoomTypeAllocations/blk:RoomTypeAllocation/@End, '-', '')"> Allocation @Start and @End dates can not be outside the Block @Start and @End dates. </sch:report>
                                                                                </sch:rule>
                                                                            </sch:pattern> 

2 个答案:

答案 0 :(得分:1)

如果至少有一个TypeAllocation错误StartEnd,或者您想检查所有问题,我不确定您是否要报告验证错误。如果您只想检查其中至少有一个是错误的,那么您可以使用

<sch:pattern>
    <sch:rule context="Block">
        <sch:report test="Types/Type/TypeAllocations/TypeAllocation[
                            translate(@Start, '-', '') > translate(current()/BlockDates/@Start, '-', '')
                            or
                            translate(@End, '-', '') > translate(current()/BlockDates/@End, '-', '')]"> Allocation @Start and @End dates can not be outside the Block @Start and @End dates. </sch:report>
    </sch:rule>
</sch:pattern> 

我想。如果您的Schematron版本不支持使用current()函数,那么在您的示例的上下文中我的建议分别是ancestor::Block而不是current()

<sch:pattern>
    <sch:rule context="Block">
        <sch:report test="Types/Type/TypeAllocations/TypeAllocation[
                            translate(@Start, '-', '') > translate(ancestor::Block/BlockDates/@Start, '-', '')
                            or
                            translate(@End, '-', '') > translate(ancestor::Block/BlockDates/@End, '-', '')]"> Allocation @Start and @End dates can not be outside the Block @Start and @End dates. </sch:report>
    </sch:rule>
</sch:pattern> 

答案 1 :(得分:0)

我能够使用以下方法实现此目的。非常感谢Martin的帮助!

<sch:rule context="Block">
    <sch:report test="Types/Type/TypeAllocations/TypeAllocation[
    translate(@Start, '-', '') &lt; translate(ancestor::Block/BlockDates/@Start, '-', '') ]
    or
    Types/Type/TypeAllocations/TypeAllocation[translate(@End, '-', '') &gt; translate(ancestor::Block/BlockDates/@End, '-', '')] ">
    Allocation @Start and @End dates can not be outside the Block @Start and @End dates.
    </sch:report>
</sch:rule>