Question

当我尝试使用gsutil命令设置通知时出现以下错误：

gsutil通知watchbucket https://groups.google.com/d/msg/google-appengine-stackoverflow/mVl-gpyIZdY/QZPvGkWeHgAJ gs：// bucket

Watching bucket gs://APPLICATION-ID.appspot.com/ with application URL https://APPLICATION-ID.appspot.com/cron ...

Watch bucket attempt failed:
  AccessDeniedException: 403 Forbidden

You attempted to watch a bucket with an application URL of:

  https://APPLICATION-ID.appspot.com/cron

which is not authorized for your project. Please ensure that you are using
Service Account authentication and that the Service Account's project is
authorized for the application URL. Notification endpoint URLs must also be
whitelisted in your Cloud Console project. To do that, the domain must also be
verified using Google Webmaster Tools. For instructions, please see:

  https://cloud.google.com/storage/docs/object-change-notification#_Authorization

AccessDeniedException: 403 Forbidden

我已按照以下网址中的所有步骤进行通知授权：

https://APPLICATION-ID.appspot.com/cron

但我仍然遇到上述错误。我错过了什么步骤？

由于

Answer 1

我自己解决了这个问题。我在添加域名时错过了“https：//”。

由于

无法在谷歌应用程序引擎中为php应用程序配置更改对象通知

1 个答案: