我们已经实现了一个解决方案,可以在提升的链接中包装切片,如下文所述:
SharePoint 2013: Promoted Links Wrap Tiles
这适用于我们,但现在我们想要使用多个提升的链接列表。在technet页面,有人已经要求我们需要的相同的东西,但是还没有答案。我注意到我们获得了与具有相同请求的人相同的Web部件ID,即:WebPartWPQ4。
通过脚本自己,我想我需要修改找到提升的链接项的行:
var numberOfPromotedLinks = $('.ms-promlink-body > .ms-tileview-tile- root').length;
我试着像这样修改它:
var numberOfPromotedLinks = $('#WebPartWPQ4 > .ms-promlink-body > .ms-tileview-tile-root').length;
然而,这不起作用。
答案 0 :(得分:0)
<script type="text/javascript" src="https://code.jquery.com/jquery-1.10.2.min.js "></script>
<script type="text/javascript">
$(document).ready(function () {
// Update this value to the number of links you want to show per row
var numberOfLinksPerRow = 3;
// local variables
var pre = "<tr><td><div class='ms-promlink-body' id='promlink_row_";
var post = "'></div></td></tr>";
var numberOfLinksInCurrentRow = numberOfLinksPerRow;
var currentRow = 1
// find the number of promoted links we're displaying
var numberOfPromotedLinks = $('.ms-promlink-body > .ms-tileview-tile-root').length;
// if we have more links then we want in a row, let's continue
if (numberOfPromotedLinks > numberOfLinksPerRow) {
// we don't need the header anymore, no cycling through links
$('.ms-promlink-root > .ms-promlink-header').empty();
// let's iterate through all the links after the maximum displayed link
for (i = numberOfLinksPerRow + 1; i <= numberOfPromotedLinks; i++) {
// if we're reached the maximum number of links to show per row, add a new row
// this happens the first time, with the values set initially
if (numberOfLinksInCurrentRow == numberOfLinksPerRow) {
// i just want the 2nd row to
currentRow++;
// create a new row of links
$('.ms-promlink-root > table > tbody:last').append(pre + currentRow + post);
// reset the number of links for the current row
numberOfLinksInCurrentRow = 0 } // move the Nth (numberOfLinksPerRow + 1) div to the current table row
$('.ms-promlink-body > .ms-tileview-tile-root:nth-child(' + (numberOfLinksPerRow + 1) + ')').appendTo($('#promlink_row_' + currentRow));
// increment the number of links in the current row
numberOfLinksInCurrentRow++; }
}
});
</script>