Question

我正在努力解决以下问题。我有3个表，sh_product，sh_discount_class和sh_shipping_lines，如下所示：

sh_product：

idp  | product  | qMin  | discount_class  | pallet_class_id_int
1      product 1  10      1                 2
2      product 2  5       1                 0

sh_discount_class

discount_id  | title  | description  | discount_value
1              5%       5% tax         0.05

sh_shipping_lines

id  | sh_id  |  idp  | quantity  | value
1     49        1      10          120
2     49        2      1           240

基本上，我想根据以下标准对所有值求和：

只要quantity sh_shipping_lines大于qMin 来自sh_product的产品的pallet_class_id_int应用相应的来自sh_discount_class
只要产品来自idp，就意味着特定产品的数量是与pallet_class_id_int对应的pallet_class_id_int数量的两倍。实际上，idp代表表

SELECT DISTINCT sh_shipping_lines.idp, sh_discount_class.discount_value, sh_discount_class.description, 
                          SUM(sh_shipping_lines.quantity) as total, sh_product.qMin, 
                          if(sh_product.qMin>0 AND sh_product.qMin<SUM(if(sh_product.pallet_class_id_int>0, 2*sh_shipping_lines.quantity, sh_shipping_lines.quantity)), 
                                SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value - SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value*sh_discount_class.discount_value, 
                                SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value) as val 
                      FROM sh_shipping_lines 
                      LEFT JOIN sh_product ON sh_product.idp = sh_shipping_lines.idp 
                      LEFT JOIN sh_discount_class ON sh_discount_class.discount_id = sh_product.discount_class 
                      WHERE sh_id=49 
                      GROUP BY sh_shipping_lines.idp

所以，在我的情况下，总和应该是（1440 - 5％）= 1368
我尝试使用以下选择，但它仍然没有计算总值，因为它应该

idp  | discount_value  | description  | total  |  qMin  | val
1      0.05              product 1      10        10      1140
2      0.05              product 2      1         5        228

期望的结果应如下所示：

Action  = (reader["Action"]) == DBNull.Value ?'\0' : Convert.ToChar(reader["Action"]),

Answer 1

为您的查询添加了一些修复程序（使用qMin并删除DISTINCT - 我认为您不需要它）。我想sh_product中的qMin列是触发折扣的给定产品的最小数量？所以IF应该是：

sh_product.qMin <= SUM

idp 2的产品数量为1（如sh_shipping_lines表中所示），因此sh_shipping_lines中的第二个产品不会触发折扣的原因。因此，IF对于产品1是正确的，但产品2进入ELSE，这就是原因最后的总和是1380。

SELECT sh_shipping_lines.idp, sh_discount_class.discount_value, sh_discount_class.description,
SUM(sh_shipping_lines.quantity) AS total, sh_product.qMin, SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value*sh_discount_class.discount_value,
    IF(sh_product.qMin>0 AND sh_product.qMin <= SUM(IF(sh_product.pallet_class_id_int>0, 2*sh_shipping_lines.quantity, sh_shipping_lines.quantity)), 
            SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value - SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value*sh_discount_class.discount_value, 
            SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value
    ) AS val

FROM sh_shipping_lines

LEFT JOIN sh_product ON sh_product.idp = sh_shipping_lines.idp
LEFT JOIN sh_discount_class ON sh_discount_class.discount_id = sh_product.discount_class

WHERE sh_id=49
GROUP BY sh_shipping_lines.idp

此查询的结果是：

idp discount_value  description total   qMin    val
1   0.05    5% tax  10  10  1140.0000
2   0.05    5% tax  1   5   240.00

这个更新版本应该可行。它非常难看，但它适用于给定的输入：

SELECT  sh_shipping_lines.idp, sh_discount_class.discount_value, sh_discount_class.description,
SUM(sh_shipping_lines.quantity) AS total, sh_product.qMin, relatedQuantity, 
    IF(sh_product.qMin > 0 AND 
            (
                sh_product.qMin <= sh_shipping_lines.quantity 
                OR 
                sh_product.qMin <= (IF(sh_product.pallet_class_id_int=0, relatedQuantity, sh_shipping_lines.quantity))
            ),
            SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value - SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value*sh_discount_class.discount_value, 
            SUM(sh_shipping_lines.quantity)*sh_shipping_lines.value
    ) AS val

FROM sh_shipping_lines

LEFT JOIN sh_product ON sh_product.idp = sh_shipping_lines.idp
LEFT JOIN sh_discount_class ON sh_discount_class.discount_id = sh_product.discount_class

LEFT JOIN (
    SELECT relatedResult.idp AS originalIdp, sh_shipping_lines.idp, sh_shipping_lines.quantity*2 AS relatedQuantity
    FROM
    (
        SELECT sh_shipping_lines.*, prod.idp AS relatedIdp
        FROM sh_product
        JOIN sh_shipping_lines ON sh_shipping_lines.idp=sh_product.idp
        LEFT JOIN
            (SELECT idp, pallet_class_id_int FROM sh_product) AS prod ON prod.pallet_class_id_int=sh_product.idp
        WHERE sh_shipping_lines.sh_id=49
    ) as relatedResult
    LEFT JOIN sh_shipping_lines ON sh_shipping_lines.idp=relatedResult.relatedIdp
) AS result ON result.originalIdp=sh_shipping_lines.idp

WHERE sh_id=49
GROUP BY sh_shipping_lines.idp;

基于复杂折扣的MySQL总和

1 个答案: